Determine the date 7 days before today using JavaScript

Question

Determine the date 7 days before today using JavaScript

I've been trying to calculate the date that is 12 days before today's date, but I'm running into an issue where it's not returning the correct result. For instance, if today is November 11, 2013 (mm/dd/yyyy), the code returns October 30, 2013 instead of the expected October 31, 2013.

Here is the code snippet I am using:

var d = new Date();
d.setDate(d.getDate() - 12);
d.setMonth(d.getMonth() + 1 - 0);
var curr_date = d.getDate();
var curr_month = d.getMonth();
var curr_year = d.getFullYear();
if (curr_month < 10 && curr_date < 10) {
    var parsedDate = "0" + curr_month + "/" + "0" + curr_date + "/" + curr_year;
    alert(parsedDate);
} else if (curr_month < 10 && curr_date > 9) {
    var parsedDate = "0" + curr_month + "/" + curr_date + "/" + curr_year;
    alert(parsedDate);
} else if (curr_month > 9 && curr_date < 10) {
    var parsedDate = curr_month + "/" + "0" + curr_date + "/" + curr_year;
    alert(parsedDate);
} else {
    var parsedDate = curr_month + "/" + curr_date + "/" + curr_year;
    alert(parsedDate);
}

javascript date

Answer 1

Answer №1

Simplified solution using pure JavaScript:

const sevenDaysAgo = new Date(Date.now() - 7 * 24 * 60 * 60 * 1000)

new Date() - creates a Date object based on calculated milliseconds.
Date.now() - provides the current time in milliseconds since 1970.
7 days * 24 hours * 60 minutes * 60 seconds * 1000 milliseconds = 604800000 (equivalent to 7 days in milliseconds).

If you don't plan to change the subtracted value, you can use the calculated constant directly. Alternatively, compute it for easier adjustment of the number of days, minutes, etc.

Recommended Date Manipulation Libraries

For frequent date and time operations, consider using Luxon if you require timezone support or opt for the lighter date-fns. Compare them here.

import { format, formatDistance, formatRelative, subDays } from 'date-fns'

format(new Date(), "'Today is a' eeee")
//=> "Today is a Friday"

formatDistance(subDays(new Date(), 3), new Date(), { addSuffix: true })
//=> "3 days ago"

formatRelative(subDays(new Date(), 3), new Date())
//=> "last Friday at 7:26 p.m."

Transition away from moment.js

The maintenance of Moment.js is winding down, with the project being labeled as legacy. While not officially obsolete, it's recommended to explore alternative libraries. More details can be found here.

Answer 2

Simplified solution using pure JavaScript:

const sevenDaysAgo = new Date(Date.now() - 7 * 24 * 60 * 60 * 1000)

new Date() - creates a Date object based on calculated milliseconds.
Date.now() - provides the current time in milliseconds since 1970.
7 days * 24 hours * 60 minutes * 60 seconds * 1000 milliseconds = 604800000 (equivalent to 7 days in milliseconds).

If you don't plan to change the subtracted value, you can use the calculated constant directly. Alternatively, compute it for easier adjustment of the number of days, minutes, etc.

Recommended Date Manipulation Libraries

For frequent date and time operations, consider using Luxon if you require timezone support or opt for the lighter date-fns. Compare them here.

import { format, formatDistance, formatRelative, subDays } from 'date-fns'

format(new Date(), "'Today is a' eeee")
//=> "Today is a Friday"

formatDistance(subDays(new Date(), 3), new Date(), { addSuffix: true })
//=> "3 days ago"

formatRelative(subDays(new Date(), 3), new Date())
//=> "last Friday at 7:26 p.m."

Transition away from moment.js

The maintenance of Moment.js is winding down, with the project being labeled as legacy. While not officially obsolete, it's recommended to explore alternative libraries. More details can be found here.

Answer 3

Answer №2

Issue successfully resolved

let daysToSubtract; // Specify number of days to subtract
const currentDate = new Date();
const previousDate = new Date(currentDate.getTime() - (daysToSubtract * 24 * 60 * 60 * 1000));
const dayOfMonth = previousDate.getDate();
const monthOfYear = previousDate.getMonth()+1;
const yearValue = previousDate.getFullYear();

Answer 4

Issue successfully resolved

let daysToSubtract; // Specify number of days to subtract
const currentDate = new Date();
const previousDate = new Date(currentDate.getTime() - (daysToSubtract * 24 * 60 * 60 * 1000));
const dayOfMonth = previousDate.getDate();
const monthOfYear = previousDate.getMonth()+1;
const yearValue = previousDate.getFullYear();

Answer 5

Answer №3

Here is the code snippet to retrieve the date from today to 7 days prior

var currentDate = new Date();
currentDate.setDate(currentDate.getDate() - 7);

var finalDate = currentDate.getDate()+'/'+ (currentDate.getMonth()+1) +'/'+currentDate.getFullYear();

Answer 6

Here is the code snippet to retrieve the date from today to 7 days prior

var currentDate = new Date();
currentDate.setDate(currentDate.getDate() - 7);

var finalDate = currentDate.getDate()+'/'+ (currentDate.getMonth()+1) +'/'+currentDate.getFullYear();

Answer 7

Answer №4

When attempting to deduct days, it can be a bit complicated. A more effective approach would involve subtracting from the timestamp and adjusting the date accordingly.

If you want to subtract 12 days, follow these steps:

   let currentDate = new Date();
   let currentTimestamp = currentDate.getTime();
   let twelveDaysAgo = currentTimestamp - (12 * 24 * 60 * 60 * 1000);
   currentDate.setUTCDate(twelveDaysAgo);

Answer 8

When attempting to deduct days, it can be a bit complicated. A more effective approach would involve subtracting from the timestamp and adjusting the date accordingly.

If you want to subtract 12 days, follow these steps:

   let currentDate = new Date();
   let currentTimestamp = currentDate.getTime();
   let twelveDaysAgo = currentTimestamp - (12 * 24 * 60 * 60 * 1000);
   currentDate.setUTCDate(twelveDaysAgo);

Answer 9

Answer №5

Updated and ready to go!

let calculateTime = (X) => {
    let timeArray = [];
    for (let count = 0; count < Math.abs(X); count++) {
        timeArray.push(new Date(new Date().getTime() - ((X >= 0 ? count : (count - count - count)) * 24 * 60 * 60 * 1000)).toLocaleString());
    }
    return timeArray;
}
console.log(calculateTime(-7)); // Next 7 Days
console.log(calculateTime(7)); // Previous 7 Days

Results

[
  '8/1/2019, 3:08:15 PM',
  '7/31/2019, 3:08:15 PM',
  '7/30/2019, 3:08:15 PM',
  '7/29/2019, 3:08:15 PM',
  '7/28/2019, 3:08:15 PM',
  '7/27/2019, 3:08:15 PM',
  '7/26/2019, 3:08:15 PM'
]
[
  '8/1/2019, 3:08:15 PM',
  '8/2/2019, 3:08:15 PM',
  '8/3/2019, 3:08:15 PM',
  '8/4/2019, 3:08:15 PM',
  '8/5/2019, 3:08:15 PM',
  '8/6/2019, 3:08:15 PM',
  '8/7/2019, 3:08:15 PM'
]

Answer 10

Updated and ready to go!

let calculateTime = (X) => {
    let timeArray = [];
    for (let count = 0; count < Math.abs(X); count++) {
        timeArray.push(new Date(new Date().getTime() - ((X >= 0 ? count : (count - count - count)) * 24 * 60 * 60 * 1000)).toLocaleString());
    }
    return timeArray;
}
console.log(calculateTime(-7)); // Next 7 Days
console.log(calculateTime(7)); // Previous 7 Days

Results

[
  '8/1/2019, 3:08:15 PM',
  '7/31/2019, 3:08:15 PM',
  '7/30/2019, 3:08:15 PM',
  '7/29/2019, 3:08:15 PM',
  '7/28/2019, 3:08:15 PM',
  '7/27/2019, 3:08:15 PM',
  '7/26/2019, 3:08:15 PM'
]
[
  '8/1/2019, 3:08:15 PM',
  '8/2/2019, 3:08:15 PM',
  '8/3/2019, 3:08:15 PM',
  '8/4/2019, 3:08:15 PM',
  '8/5/2019, 3:08:15 PM',
  '8/6/2019, 3:08:15 PM',
  '8/7/2019, 3:08:15 PM'
]

Answer 11

Answer №6

Date.prototype.subtractDays = function(days) {
    // Subtract days from given date
    var date = new Date(this.valueOf());
    date.setDate(date.getDate() - days);
    return date;
}

let today = new Date()

console.log(today.subtractDays(7))

Answer 12

Date.prototype.subtractDays = function(days) {
    // Subtract days from given date
    var date = new Date(this.valueOf());
    date.setDate(date.getDate() - days);
    return date;
}

let today = new Date()

console.log(today.subtractDays(7))

Answer 13

Answer №7

If you need to retrieve the past days as an array, you can utilize this code snippet:

Check the console for the output

const GetDays = (d, Mention_today = false) => {
//Mention today means the array will include today's date
var DateArray = [];
var days = d;
for(var i=0; i<days; i++){
if(!Mention_today && i==0){i=1; days+=1;}
var date = new Date();
var last = new Date(date.getTime() - (i * 24 * 60 * 60 * 1000));
var day = last.getDate();
var month = last.getMonth() + 1;
var year = last.getFullYear();
const fulld = (Number(year)+'-'+Number(month)+'-'+Number(day)); // Customize date format here
DateArray.push(fulld);
}
return DateArray;
}

console.log(GetDays(5)) // Outputs past 5 days in the format YY-mm-dd

Answer 14

If you need to retrieve the past days as an array, you can utilize this code snippet:

Check the console for the output

const GetDays = (d, Mention_today = false) => {
//Mention today means the array will include today's date
var DateArray = [];
var days = d;
for(var i=0; i<days; i++){
if(!Mention_today && i==0){i=1; days+=1;}
var date = new Date();
var last = new Date(date.getTime() - (i * 24 * 60 * 60 * 1000));
var day = last.getDate();
var month = last.getMonth() + 1;
var year = last.getFullYear();
const fulld = (Number(year)+'-'+Number(month)+'-'+Number(day)); // Customize date format here
DateArray.push(fulld);
}
return DateArray;
}

console.log(GetDays(5)) // Outputs past 5 days in the format YY-mm-dd

Answer 15

Answer №8

Step One: Retrieve the current date.

 const currentDate = new Date();

Step Two: Determine the desired date. Note: Modifying the currentDate using setDate will impact this variable.

const sevenDaysAgoDate = new Date(new Date().setDate(new Date().getDate() - 7));

Date set for 7 days in the future

const futureDate = new Date(new Date().setDate(new Date().getDate() + 7));

Answer 16

Step One: Retrieve the current date.

 const currentDate = new Date();

Step Two: Determine the desired date. Note: Modifying the currentDate using setDate will impact this variable.

const sevenDaysAgoDate = new Date(new Date().setDate(new Date().getDate() - 7));

Date set for 7 days in the future

const futureDate = new Date(new Date().setDate(new Date().getDate() + 7));

Answer 17

Answer №9

Check out this handy function that can give you a date in either the past or future:

If plusMinus = -1, it will give you a date in the past.
If plusMinus = 1, it will give you a date in the future.

function getDate(inDays, plusMinus) {
    const today = new Date(); 
    return new Date(today.getFullYear(),
                    today.getMonth(),
                    today.getDate() + (inDays * plusMinus));
}

Answer 18

Check out this handy function that can give you a date in either the past or future:

If plusMinus = -1, it will give you a date in the past.
If plusMinus = 1, it will give you a date in the future.

function getDate(inDays, plusMinus) {
    const today = new Date(); 
    return new Date(today.getFullYear(),
                    today.getMonth(),
                    today.getDate() + (inDays * plusMinus));
}

Answer 19

Answer №10

Make your life simpler with the dayjs library.

import dayjs from 'dayjs';

const findDate = (pastDays) => {
    const current = dayjs();
    console.log(current.subtract(pastDays, 'day').format('mm-dd-yyyy'));
    return current.subtract(pastDays, 'day').toDate();
}

Answer 20

Make your life simpler with the dayjs library.

import dayjs from 'dayjs';

const findDate = (pastDays) => {
    const current = dayjs();
    console.log(current.subtract(pastDays, 'day').format('mm-dd-yyyy'));
    return current.subtract(pastDays, 'day').toDate();
}

Answer 21

Answer №11

Looking for the ideal solution? When X represents your day:

let calendarDates = [];
for (let count = 0; count < X; count++) {
  let currentDate = new Date();

  let targetDay = currentDate.getDate() - count; //Current Date
  currentDate.setDate(targetDay);
  let dayOfMonth = currentDate.getDate();
  let monthOfYear = currentDate.getMonth() + 1;
  let yearShort = currentDate
    .getFullYear()
    .toString()
    .substr(-2);

  calendarDates.push(monthOfYear + '/' + dayOfMonth + '/' + yearShort); //customize format as needed
}
//output mm/d/yy

Answer 22

Looking for the ideal solution? When X represents your day:

let calendarDates = [];
for (let count = 0; count < X; count++) {
  let currentDate = new Date();

  let targetDay = currentDate.getDate() - count; //Current Date
  currentDate.setDate(targetDay);
  let dayOfMonth = currentDate.getDate();
  let monthOfYear = currentDate.getMonth() + 1;
  let yearShort = currentDate
    .getFullYear()
    .toString()
    .substr(-2);

  calendarDates.push(monthOfYear + '/' + dayOfMonth + '/' + yearShort); //customize format as needed
}
//output mm/d/yy

Answer 23

Answer №12

Appreciate the assistance. A basic function did the trick for me

const subtractDayFromDate = (date, days) => {
  const newDate = new Date(date);
  newDate.setDate(newDate.getDate() - days);
  return newDate;
};

Answer 24

Appreciate the assistance. A basic function did the trick for me

const subtractDayFromDate = (date, days) => {
  const newDate = new Date(date);
  newDate.setDate(newDate.getDate() - days);
  return newDate;
};

Determine the date 7 days before today using JavaScript

Answer №1

Simplified solution using pure JavaScript:

Recommended Date Manipulation Libraries

Transition away from moment.js

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

Answer №8

Answer №9

Answer №10

Answer №11

Answer №12

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