Combine two queries in JavaScript by using arrays

I have a unique challenge where I can only post once every 90 minutes, so here's my double question. First up, I need to create a function that can replace a specific character in a string with a space.

//======================  EXAMPLE  ========================
var str = "I,Really,Like,Pizza";
characterRemover(str, ",");
"I Really Like Pizza"; // <======  EXPECTED OUTPUT
//=========================================================

After trying out this code, I encountered a problem where the function didn't work as expected.

function chracterRemover(str, cha){
    var replaced = str.split('cha').join(' ');
    return replaced;
}

Instead of replacing the character with a space, it returned the same string.

The second part of my question involves creating a function that can determine if the input data type is an array or not.

//======================  EXAMPLE  ========================
var one = { name: "antonello" };
false; // <======  EXPECTED OUTPUT
var two = ["name", "antonello"];
true; // <======  EXPECTED OUTPUT
var three = [[], [], {}, "antonello", 3, function() {}];
true; // <======  EXPECTED OUTPUT
//=========================================================

For this part, I attempted the following function.

function isArrayFun(array){
    if {
        typeof array = 'array';
        return "Array";
    } else {
        return "Not an array"
    }
}

However, my code resulted in an error message:

Uncaught SyntaxError: Unexpected token '{'

I'm not sure why this error occurred. Any help will be greatly appreciated. Thank you!

Answer №1

// Example One
const str = "I,Love,Eating,Pasta";
console.log(str.split(',').join(' '));

// Example Two
function isArrayCheck(arr){
  return Array.isArray(arr);
}

const singleObj = { name: "john" };
console.log(isArrayCheck(singleObj));

const arrayOne = ["apple", "banana"];
console.log(isArrayCheck(arrayOne));

const mixedArr = [[], [], {}, "carrot", 5, function() {}];
console.log(isArrayCheck(mixedArr));

Answer №2

Solution 1:

Remember to use a variable instead of quoting it as a string by using cha. Here's an example:

function replaceCharacter(str, cha) {
  var replacedString = str.split(cha).join(' ');
  return replacedString;
}

var sentence = "I,Really,Like,Pizza";
console.log(replaceCharacter(sentence, ","));

Solution 2:

When checking if a value is an array, use Array.isArray() instead of typeof, and fix the syntax error in your if statement. Make sure the condition is within ().

function checkIfArray(arr) {
  if (Array.isArray(arr)) {
    return "It is an Array";
  } else {
    return "Not an Array"
  }
}

var itemOne = { name: "John" };
console.log(checkIfArray(itemOne));
var itemTwo = ["name", "John"];
console.log(checkIfArray(itemTwo));
var itemThree = [[], [], {}, "John", 3, function() {}];
console.log(checkIfArray(itemThree));

Answer №3

Primary inquiry.

  1. The function name differs from the one you invoked
  2. To properly split your string, utilize .split(cha) instead of 'cha'. Using split cha will effectively separate your string by the specified parameter you passed in. On the other hand, 'cha' searches for the exact string 'cha'

Demonstration:

var str = "I,Truly,Enjoy,Pasta";

function removeChar(str, char){
    var modifiedStr = str.split(char).join(' ');
    return modifiedStr;
}
console.log(removeChar(str, ","));

An alternative approach would be employing a simple RegExp rather than using split and join, thereby elevating the functionality by introducing a third parameter where you can specify the replacement:

var str = "I,Truly,Enjoy,Pasta";

function removeChar(str, char, replaceChar){
    var regex = new RegExp(char, "g");
    return str.replace(regex, replaceChar);
}
console.log(removeChar(str, ",", " "));
console.log(removeChar(str, ",", "."));

Secondary query:

A similar function already exists

Array.isArray(value)

You can input any data type into this function; if it's an array, it will return true

Example:

let val1 = [1,5,6];
let val2 = {a: 47};
let val3 = 5;
let val4 = "hello";

console.log(Array.isArray(val1))
console.log(Array.isArray(val2))
console.log(Array.isArray(val3))
console.log(Array.isArray(val4))

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