I have a situation where I am working with two arrays of objects.
arr1 = [{ name: "John" }, { name: "Frank" }];
arr2 = [
{ name: "John", age: 35 },
{ name: "Frank", age: 22 },
{ name: "Kate", age: 23 },
{ name: "Donald", age: 18 },
];
My task is to compare these arrays. If the key/value pair name matches between the two arrays, I need to add the key/value pair selected: true to the object in the second array.
If you want to efficiently store and compare the names in two arrays, you can utilize the Set method for array manipulation. By creating a set from the first array's names and then mapping over the second array, you can easily identify the common names as shown below:
const arr1 = [{ name: "John" }, { name: "Frank" }];
const arr2 = [
{ name: "John", age: 35 },
{ name: "Frank", age: 22 },
{ name: "Kate", age: 23 },
{ name: "Donald", age: 18 },
];
const arr1Set = new Set(arr1.map(o => o.name));
const result = arr2.map(o => arr1Set.has(o.name) ? { ...o, selected: true }: o);
console.log(result);If you want to check for matching items between two arrays, utilize the map method to iterate through each item in the second array (arr2). Then, use the .some function to verify if an item with the same name exists in the first array (arr1). In your return statement, consider using a ternary syntax: if the element is "isSelected", return a merged object created using the spread operator ...; otherwise, return the original unaltered object.
const arr1 = [{ name: "Mary" }, { name: "Bob" }];
const arr2 = [
{ name: "Mary", age: 30 },
{ name: "Bob", age: 40 },
{ name: "Alice", age: 25 },
{ name: "David", age: 35 },
];
const result = arr2.map(obj2 => {
const isSelected = arr1.some(({name}) => name === obj2.name);
return isSelected ? {...obj2, selected: true} : obj2;
});
console.log(result);To transform the structure of arr2, you can utilize the map function to verify the presence of an item from arr1.
const arr1 = [{ name: 'Alice' }, { name: 'Bob' }];
const arr2 = [
{ name: 'Alice', age: 30 },
{ name: 'Bob', age: 25 },
{ name: 'Eve', age: 21 },
];
const result = arr2.map((obj) => {
return arr1.find(({ name }) => name === obj.name)
? { ...obj, match: true }
: obj;
});
console.log(result);
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