Determine if a String Includes Characters Using If and Else Conditions

I am dealing with a string called uppercase, where if it contains letters nothing happens. However, if there are no letters in the string, then it evaluates uppercase. This is what I'm currently trying to accomplish using an if and else statement:

  
  if(uppercase.substring(0,9) == "CALCULATE")
  {
    if(uppercase.substring(10,uppercase.length.contains("[a-zA-Z]+")))
    {
    } else{
      var ans = eval(uppercase.substring(9,uppercase.length));
      sendSpecialChat = [true, ans];
      }
  }

However, my code isn't working as expected. Can anyone help me identify what might be going wrong?

javascript

Answer №1

It seems that the problem lies in this particular section:

uppercase.substring(10,uppercase.length.contains("[a-zA-Z]+")

To check if there are any letters present in the portion of uppercase beyond the 10th character (keeping in mind zero indexing), you can utilize substring along with a suitable regular expression, for instance:

/[a-z]/i.test(uppercase.substring(10,uppercase.length))


var uppercase = "0123456789Hey"

console.log('"' + uppercase + '" : ' + 
            /[a-z]/i.test(uppercase.substring(10,uppercase.length)));

var uppercase = "0123456789*&^"

console.log('"' + uppercase + '" : ' + 
            /[a-z]/i.test(uppercase.substring(10,uppercase.length)));

You could also opt for using a simple regular expression like so:

var uppercase = "0123456789Hey";

console.log('"' + uppercase + '" : ' + /^.{10}[a-z]/i.test(uppercase));

var uppercase = "0123456789*&^";

console.log('"' + uppercase + '" : ' + /^.{10}[a-z]/i.test(uppercase));

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