Decoding the JSON Feedback in AngularJS

Recently, I started delving into Angular Java scripting and have been experimenting with calling a web service and utilizing the returned JSON in a Controller as seen below:


var nameBarcodePrjList = []; 
var url = $rootScope.BaseURL + "PROJECT";
var configPrj = {
    headers: {
        'Authorization': `Basic ${$scope.key}`
    }
};
$http.get(url, configPrj)
.then(
function (response) { // success async
    var nameBarcodePrjData = response.data.value;

    for (var i = 0; i < nameBarcodePrjData.length; i++) {
        var namePrjBarcode = {
            Name: "",
            Barcode: ""
        };
        namePrjBarcode.Name = nameBarcodePrjData[i].Name;
        namePrjBarcode.Barcode = nameBarcodePrjData[i].Barcode;
        console.log(nameBarcodePrjData[i].Name);
        nameBarcodePrjList.push(namePrjBarcode);
    };
    return nameBarcodePrjList;
    console.log("Success");

Even though the response is in JSON format like this https://i.sstatic.net/dV4NV.png, it seems that the nameBarcodePrjList remains empty when it should include both Name and Barcode. Could there be something missing in how I am parsing the response here?

Answer №1

It appears that you are attempting to use return whatever; in the success callback of an asynchronous call, which is not allowed as async calls do not work like that.

To achieve this, you need to utilize a promise. In the context of angular, you can make use of the $q service for this purpose.

To work around this issue, one approach is to declare a variable outside the scope of the $http.get() method and then populate it within the success callback so that it is properly initialized and accessible elsewhere.

Here's an example:


var globalDataStore = [];
$http.get(url, configPrj)
    .then(
    function (response) {
        globalDataStore = response.data.value;
        workWithTheGlobalDataStore();
    });
function workWithTheGlobalDataStore(){
    var firstItem = globalDataStore.length > 0 ? globalDataStore[0] : '';
    console.log('firstItem : ', firstItem);
}

Answer №2

Everything looks good if you're able to run

console.log(nameBarcodePrjData[i].Name)
.

The issue may lie with the

nameBarcodePrjList.push(nameBarcode);
line of code.

It seems that 'nameBarcode' is not defined anywhere in your code, which could be causing the error.

Thank you!

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