Creating a singly linked list in JavaScript that behaves like a single indexed array

Question

Creating a singly linked list in JavaScript that behaves like a single indexed array

I am faced with an array structure like this:

    var arrays = [
  {
    "value": "$6"
  },
  {
    "value": "$12"
  },
  {
    "value": "$25"
  },
  {
    "value": "$25"
  },
  {
    "value": "$18"
  },
  {
    "value": "$22"
  },
  {
    "value": "$10"
  }
];

My goal is to transform this array into a single indexed array that looks like the following:

[{
    "value": "$6",
    "Next": {
        "value": "$12",
        "Next": {
            "value": "$25",
            "Next": {
                "value": "$25",
                "Next": {
                    "value": "$28",
                    "Next": {
                        "value": "$22",
                        "Next": {
                            "value": "$10"
                        }
                    }
                }
            }
        }
    }
}]

I am looking for a way to push the elements of the second array into the first array in the format shown above using JavaScript linked lists.

javascript arrays

Answer 1

Answer №1

Utilizing the `Array#reduce` method, transform the given array into a linked list where each iteration creates an object/node and passes the reference to `next` for the next iteration. It is essential to maintain a reference to the `root/head` object as we traverse through the linked list.

var arrays = [{
    "value": "$6"
  },
  {
    "value": "$12"
  },
  {
    "value": "$25"
  },
  {
    "value": "$25"
  },
  {
    "value": "$18"
  },
  {
    "value": "$22"
  },
  {
    "value": "$10"
  }
];
var root = {};
arrays.reduce((acc, { value }) => {
  acc.next = { value };
  return acc.next;
}, root);
var result = [root.next];
console.log(result);

We trust this explanation serves you well!

Answer 2

Utilizing the `Array#reduce` method, transform the given array into a linked list where each iteration creates an object/node and passes the reference to `next` for the next iteration. It is essential to maintain a reference to the `root/head` object as we traverse through the linked list.

var arrays = [{
    "value": "$6"
  },
  {
    "value": "$12"
  },
  {
    "value": "$25"
  },
  {
    "value": "$25"
  },
  {
    "value": "$18"
  },
  {
    "value": "$22"
  },
  {
    "value": "$10"
  }
];
var root = {};
arrays.reduce((acc, { value }) => {
  acc.next = { value };
  return acc.next;
}, root);
var result = [root.next];
console.log(result);

We trust this explanation serves you well!

Answer 3

Answer №2

This code snippet will process the array in a reverse direction, storing the previous value and appending it to the current one before returning the final output.

Give it a try!

function processData(data){
  var result = [];
  var length = data.length;
  var prevValue = {};
  for(var index = length-1; index >= 0; index--){
    var tempObj = {};
    tempObj["value"] = data[index].value;
    if(index !== length){
       tempObj["Next"] = prevValue;
    }
    prevValue = tempObj;
  }
  result.push(prevValue);
  return result;
}

Answer 4

This code snippet will process the array in a reverse direction, storing the previous value and appending it to the current one before returning the final output.

Give it a try!

function processData(data){
  var result = [];
  var length = data.length;
  var prevValue = {};
  for(var index = length-1; index >= 0; index--){
    var tempObj = {};
    tempObj["value"] = data[index].value;
    if(index !== length){
       tempObj["Next"] = prevValue;
    }
    prevValue = tempObj;
  }
  result.push(prevValue);
  return result;
}

Answer 5

Answer №3

give this a shot

let list=[];
for(let x=0; x<elements.length; x++){ 
   list.push(
      {"content":elements[x]["content"], "following":elements[x+1]}
)}

Answer 6

give this a shot

let list=[];
for(let x=0; x<elements.length; x++){ 
   list.push(
      {"content":elements[x]["content"], "following":elements[x+1]}
)}

Creating a singly linked list in JavaScript that behaves like a single indexed array

Answer №1

Answer №2

Answer №3

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