I have a collection of three sets, each containing three elements:
Set1 = [[apple, 2, 4],
[banana, 5, 5],
[cherry, 4, 1]]
Set2 = [[banana, 1, 7],
[cherry, 3, 8],
[date, 5, 4]]
Set3 = [[apple, 5, 2],
[banana, 0, 9],
[date, 3, 1]]
The desired output format is as follows:
[[apple, 2, 4, 0, 0, 5, 2],
[banana, 5, 5, 1, 7, 0, 9],
[cherry, 4, 1, 3, 8, 0, 0],
[date, 0, 0, 5, 4, 3, 1]]
How can I transform the sets to achieve this output?
This will get the job done, although it may not be the most aesthetically pleasing ;)
const combineSiblings = (...elements) => {
return elements.reduce((acc, current, index) => {
current.flat();
acc.push(...current);
// Sort the array alphabetically by its first element
return acc.sort((a ,b) => ((a[0] > b[0]) ? 1 : (a[0] < b[0]) ? -1 : 0));
}, []);
}
let combined = combineSiblings(V1, V2, V3);
/*
Manually concatenate the desired output since the placement of 0, 0 was not specified.
*/
let finalResult = [
[
...combined[0].flat(),
...[0,0],
...combined[1].slice(1,3).flat()
],
[
...combined[2].flat(),
...combined[3].slice(1,3).flat(),
...combined[4].slice(1,3).flat()
],
[
...combined[5].flat(),
...combined[6].slice(1,3).flat(),
...[0,0]
],
[
combined[7][0],
...[0,0],
...combined[7].slice(1,3).flat(),
...combined[8].slice(1,3).flat()
]
];
To efficiently organize the values, you can store them in an object and then create an array with default empty values to assign the collected values.
var v1 = [['a', 2, 4], ['b', 5, 5], ['c', 4, 1]],
v2 = [['b', 1, 7], ['c', 3, 8], ['d', 5, 4]],
v3 = [['a', 5, 2], ['b', 0, 9], ['d', 3, 1]],
parts = [v1, v2, v3],
empty = Array(parts.length * 2 + 1).fill(0);
temp = parts.reduce((r, a, i) => {
a.forEach(([key, ...values]) => {
r[key] = r[key] || { 0: key };
for (let j = 0; j < values.length; j++) {
r[key][i * values.length + j + 1] = values[j];
}
});
return r;
}, {}),
result = Object.values(temp).map(v => Object.assign([], empty, v));
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