Change HTML table information into an array with the help of JavaScript

I am facing an issue where the array is displaying as undefined even though I am storing table data in an array. Check out more about arrays here.

Attempting to retrieve each problem's row in the form of an array

function getAllProblemRowElements() {
    //var k = document.querySelector("#app > div > div > div > div.table-responsive > table > tbody");
    const tableContents = document.querySelector("#app > div > div > div > div.table-responsive > table > tbody");
    const sources = Array.from(tableContents,source=>tableContents[0]);
    return sources;
} 

Please help me resolve this issue

Answer №1

Converting Table Content to Array in JavaScript

var tableData = Array.prototype.map.call(document.querySelectorAll('#myTable tr'), function(row){
  return Array.prototype.map.call(row.querySelectorAll('td'), function(td){
    return td.innerHTML;
    });
  });

console.log(tableData)
<table id="myTable">
<tr>
  <td>1</td>
  <td>a</td>
</tr>
<tr>
  <td>2</td>
  <td>b</td>
</tr>
<tr>
  <td>3</td>
  <td>c</td>
</tr>
</table>

Answer №2

Check out this updated ES6 code snippet:

const tableData = [...document.querySelectorAll('#myTable tr')]
  .map(row => [...row.querySelectorAll('td')]
    .map(cell => cell.textContent));

console.log(tableData)
<table>
  <tbody id="myTable">
    <tr>
      <td>1</td>
      <td>a</td>
    </tr>
    <tr>
      <td>2</td>
      <td>b</td>
    </tr>
    <tr>
      <td>3</td>
      <td>c</td>
    </tr>
  </tbody>
</table>

Answer №3

It seems like the row causing trouble in your query is the title. To address this issue, you can utilize the querySelectorAll method within the context of the document object to retrieve all rows and then convert them into an array. The code snippet below demonstrates how this can be achieved:

function findProblemRows() {
    const tableRows = document.querySelectorAll("#app > div > div > div > div.table-responsive > table > tbody > tr");
    const problemSources = Array.from(tableRows, source=>source.children[2].getAttribute("value"))
    return problemSources;
}

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