Can you transform an Array into a NodeList using JavaScript? Exploring a coding challenge involving linked lists on LeetCode

I have been working on a leetcode problem and I believe I have found the solution. However, there seems to be a discrepancy in my function's output - it returns an Array whereas the problem specifically requires a NodeList.

I am struggling to figure out how to either create a NodeList without involving the DOM or convert my existing Array into a NodeList.

Here is the problem description:

Merge two sorted linked lists and return it as a new sorted list. The new list should be made by splicing together the nodes of the first two lists.

Example:

Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4

Below is my code snippet :

const listOne = [1, 2, 4];
const listTwo = [1, 3, 4];

function myFunction(l1, l2) {
  let lslength;
  let newList = [];
  if (l1.length >= l2.length) {
    lslength = l1.length;
  } else {
    lslength = l2.length;
  }
  for (let i = 0; i < lslength; i++) {
    if (l1[i] === l2[i]) {
      newList.push(l1[i]);
      newList.push(l2[i]);
    } else if (l1[i] < l2[i]) {
      newList.push(l1[i]);
      newList.push(l2[i]);
    } else if (l1[i] > l2[i]) {
      newList.push(l2[i]);
      newList.push(l1[i]);
    } else if (l1[i]) {
      newList.push(l1[i]);
    } else {
      newList.push(l2[i]);
    }
  }
  return newList;
}

myFunction(listOne, listTwo);

--------UPDATE--------- I now realize that my misunderstanding of the problem was due to overlooking the fact that it pertains to Linked Lists. Thank you for pointing that out.

Answer №1

There is no need to perform that action.

The test cases are formatted as arrays for user convenience. However, it's important to note that a LinkedList and an array are distinct data types. In this case, the function should return a merged linked list, not a merged array.

To merge two linked lists, we can utilize a sentinel node. The following code will be accepted:

/**
 * Definition for singly-linked list.
 * function ListNode(val, next) {
 *     this.val = (val===undefined ? 0 : val)
 *     this.next = (next===undefined ? null : next)
 * }
 */
/**
 * @param {ListNode} l1
 * @param {ListNode} l2
 * @return {ListNode}
 */
var mergeTwoLists = function(l1, l2) {
    var sentinel = {
        val: -1,
        next: null
    };

    var curr = sentinel;
    while (l1 && l2) {
        if (l1.val > l2.val) {
            curr.next = l2;
            l2 = l2.next;
        } else {
            curr.next = l1;
            l1 = l1.next;
        }
        curr = curr.next;
    }

    curr.next = l1 || l2;

    return sentinel.next;
};

References

  • For more information, refer to the Discussion Board. You'll find numerous approved solutions in different programming languages, along with efficient algorithms and analysis of time/space complexity1, 2.

  • Comparison between LinkedList and Array

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