Arrange objects array by quarterly-yearly data in JavaScript

Question

Arrange objects array by quarterly-yearly data in JavaScript

My data set consists of objects as shown below:

[  
   {  
      "name":"Q1'2016",
      "y":0
   },
   {  
      "name":"Q2'2016",
      "y":0
   },
   {  
      "name":"Q3'2016",
      "y":0
   },
   {  
      "name":"Q4'2015",
      "y":0
   }
]

I need to arrange these objects in quarterly order, starting with Q4'2015, followed by Q1'2016, and so on.

Is there a way to accomplish this sorting?

javascript arrays json sorting

Answer 1

Answer №1

If you want to organize your object based on quarter-year information, you can utilize the sort method with a callback function. By mapping the quarters to month values, you can convert them into year/month dates for comparison purposes when sorting the data. Here's an example:

var data = [{
  "name": "Q1'2016",
  "y": 0
}, {
  "name": "Q2'2016",
  "y": 0
}, {
  "name": "Q3'2016",
  "y": 0
}, {
  "name": "Q4'2015",
  "y": 0
}];

var quarterToMonthMap = {
  "Q1": 0,
  "Q2": 3,
  "Q3": 6,
  "Q4": 9
}

function sortByQuarterYear(lhs, rhs) {
  var lhsQuarterYear = lhs.name.split("'");
  var rhsQuarterYear = rhs.name.split("'");
  var lhsDate = new Date(lhsQuarterYear[1], quarterToMonthMap[lhsQuarterYear[0]]);
  var rhsDate = new Date(rhsQuarterYear[1], quarterToMonthMap[rhsQuarterYear[0]]);
  return lhsDate.getTime() - rhsDate.getTime();
}

document.write(JSON.stringify(data.sort(sortByQuarterYear)));

Answer 2

If you want to organize your object based on quarter-year information, you can utilize the sort method with a callback function. By mapping the quarters to month values, you can convert them into year/month dates for comparison purposes when sorting the data. Here's an example:

var data = [{
  "name": "Q1'2016",
  "y": 0
}, {
  "name": "Q2'2016",
  "y": 0
}, {
  "name": "Q3'2016",
  "y": 0
}, {
  "name": "Q4'2015",
  "y": 0
}];

var quarterToMonthMap = {
  "Q1": 0,
  "Q2": 3,
  "Q3": 6,
  "Q4": 9
}

function sortByQuarterYear(lhs, rhs) {
  var lhsQuarterYear = lhs.name.split("'");
  var rhsQuarterYear = rhs.name.split("'");
  var lhsDate = new Date(lhsQuarterYear[1], quarterToMonthMap[lhsQuarterYear[0]]);
  var rhsDate = new Date(rhsQuarterYear[1], quarterToMonthMap[rhsQuarterYear[0]]);
  return lhsDate.getTime() - rhsDate.getTime();
}

document.write(JSON.stringify(data.sort(sortByQuarterYear)));

Answer 3

Answer №2

If you want to sort by year and quarter, you can achieve this using the following ES6 snippet. (It's also possible with ES5, but I prefer ES6)

input.map((obj, index) => obj.name.split("'").reverse().concat(index)).sort().map(arr => input[arr[2]]);

Let's break this down for better understanding

input.map((obj, index) => obj.name.split("'").reverse().concat(index))

The map() function creates a new array by calling a given function on each element in the original array.
_{https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map}

In our case, we split the "name" property of each object by the character "'", reverse the resulting array, and add the current index to it.

This operation results in an array like:

[
    ["2016", "Q1", 0], 
    ["2016", "Q2", 1], 
    ["2016", "Q3", 2], 
    ["2015", "Q4", 3]
]

We then use .sort,

The sort() method arranges the elements of an array and returns it. The default sorting order is based on Unicode points.
_{https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort}

After sorting, the array looks like:

[
    ["2015", "Q4", 3], 
    ["2016", "Q1", 0], 
    ["2016", "Q2", 1], 
    ["2016", "Q3", 2]
]

Now, although the indexes are not ordered within, we can utilize this to establish order.

By another application of map, we retrieve the original object related to the stored index in our temporary arrays.

.map(arr => input[arr[2]]);

Upon executing this sequence, the resultant array will be structured as follows:

[
    {
        name: "Q4'2015",
        y: 0
    }, {
        name: "Q1'2016",
        y: 0
    }, {
        name: "Q2'2016",
        y: 0
    }, {
        name: "Q3'2016",
        y: 0
    }
]

Give it a try with the provided demo:

let input = [  
   {  
      "name":"Q1'2016",
      "y":0
   },
   {  
      "name":"Q2'2016",
      "y":0
   },
   {  
      "name":"Q3'2016",
      "y":0
   },
   {  
      "name":"Q4'2015",
      "y":0
   }
];
    
input = input.map((obj, index) => obj.name.split("'").reverse().concat(index)).sort().map(arr => input[arr[2]]);

console.log(input);

To replicate this process using ES5:

input.map(function(obj, index){
    return obj.name.split("'").reverse().concat(index);
}).sort().map(function(arr){
    return input[arr[2]];
});

Answer 4

If you want to sort by year and quarter, you can achieve this using the following ES6 snippet. (It's also possible with ES5, but I prefer ES6)

input.map((obj, index) => obj.name.split("'").reverse().concat(index)).sort().map(arr => input[arr[2]]);

Let's break this down for better understanding

input.map((obj, index) => obj.name.split("'").reverse().concat(index))

The map() function creates a new array by calling a given function on each element in the original array.
_{https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map}

In our case, we split the "name" property of each object by the character "'", reverse the resulting array, and add the current index to it.

This operation results in an array like:

[
    ["2016", "Q1", 0], 
    ["2016", "Q2", 1], 
    ["2016", "Q3", 2], 
    ["2015", "Q4", 3]
]

We then use .sort,

The sort() method arranges the elements of an array and returns it. The default sorting order is based on Unicode points.
_{https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort}

After sorting, the array looks like:

[
    ["2015", "Q4", 3], 
    ["2016", "Q1", 0], 
    ["2016", "Q2", 1], 
    ["2016", "Q3", 2]
]

Now, although the indexes are not ordered within, we can utilize this to establish order.

By another application of map, we retrieve the original object related to the stored index in our temporary arrays.

.map(arr => input[arr[2]]);

Upon executing this sequence, the resultant array will be structured as follows:

[
    {
        name: "Q4'2015",
        y: 0
    }, {
        name: "Q1'2016",
        y: 0
    }, {
        name: "Q2'2016",
        y: 0
    }, {
        name: "Q3'2016",
        y: 0
    }
]

Give it a try with the provided demo:

let input = [  
   {  
      "name":"Q1'2016",
      "y":0
   },
   {  
      "name":"Q2'2016",
      "y":0
   },
   {  
      "name":"Q3'2016",
      "y":0
   },
   {  
      "name":"Q4'2015",
      "y":0
   }
];
    
input = input.map((obj, index) => obj.name.split("'").reverse().concat(index)).sort().map(arr => input[arr[2]]);

console.log(input);

To replicate this process using ES5:

input.map(function(obj, index){
    return obj.name.split("'").reverse().concat(index);
}).sort().map(function(arr){
    return input[arr[2]];
});

Answer 5

Answer №3

By utilizing the .sort() method alongside a comparator function, it becomes possible to easily transform values like "Q1'2016" into "2016Q1". This transformation allows for straightforward alphanumeric comparisons such as "2016Q1" > "2015Q4".

function sortQuarters(arr) {
  function reformat(v) {
    return v.replace(/(Q\d)'(\d{4})/, "$2$1");
  }
  return arr.sort(function(a, b) {
    return reformat(a.name).localeCompare(reformat(b.name));
  });
}

console.log(sortQuarters([  
   { "name":"Q1'2016", "y":0 },
   { "name":"Q3'2016", "y":0 },
   { "name":"Q2'2016", "y":0 },
   { "name":"Q4'2015", "y":0 }
]));

(It is important to note that this reformatting only occurs within temporary variables during sorting and does not alter the original values in the array. Additionally, the provided function changes the order of the passed array but returns the same array rather than creating a new one.)

Answer 6

By utilizing the .sort() method alongside a comparator function, it becomes possible to easily transform values like "Q1'2016" into "2016Q1". This transformation allows for straightforward alphanumeric comparisons such as "2016Q1" > "2015Q4".

function sortQuarters(arr) {
  function reformat(v) {
    return v.replace(/(Q\d)'(\d{4})/, "$2$1");
  }
  return arr.sort(function(a, b) {
    return reformat(a.name).localeCompare(reformat(b.name));
  });
}

console.log(sortQuarters([  
   { "name":"Q1'2016", "y":0 },
   { "name":"Q3'2016", "y":0 },
   { "name":"Q2'2016", "y":0 },
   { "name":"Q4'2015", "y":0 }
]));

(It is important to note that this reformatting only occurs within temporary variables during sorting and does not alter the original values in the array. Additionally, the provided function changes the order of the passed array but returns the same array rather than creating a new one.)

Arrange objects array by quarterly-yearly data in JavaScript

Answer №1

Answer №2

Answer №3

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