analyzing a string against an embedded structure

Question

analyzing a string against an embedded structure

As someone who is just starting to learn code, I apologize if my question seems trivial.

I have a nested object database that I need to search for a character name and retrieve the corresponding owner of that character. Unfortunately, all the solutions I've come across so far only address searching at the top level or are specifically designed for arrays, leaving me feeling stuck and out of options. Is it possible to perform a deep search for a name like 'Farah' within the database and then somehow link it back to 'olis characters'?

Thank you in advance for any guidance or tips you may be able to provide!

{
  "olis characters": {
    "0": {
      "name": "Farah",
      "class": "rogue",
      "level": 74
    },
    "1": {
      "name": "Grop",
      "class": "paladin",
      "level": 31
    },
    "2": {
      "name": "Skolmr",
      "class": "druid",
      "level": 85,
    }
  },
  "chris characters": {
    "0": {
      "name": "Trygve",
      "class": "bard",
      "level": 28
    },
    "1": {
      "name": "Brusi",
      "class": "rogue",
      "level": 10
    },
    "2": {
      "name": "Steini",
      "class": "skald",
      "level": 58
    }
  }
}

javascript json object nested

Answer 1

Answer №1

It appears that your data structure is a bit unusual. The presence of numeric keys in an object suggests it should be an array instead. However, you can still extract the desired information by utilizing the Object.values method.

let data = {"olis characters": {"0": {"name": "Farah","class": "rogue","level": 74},"1": {"name": "Grop","class": "paladin","level": 31},"2": {"name": "Skolmr","class": "druid","level": 85,}},"chris characters": {"0": {"name": "Trygve","class": "bard","level": 28},"1": {"name": "Brusi","class": "rogue","level": 10},"2": {"name": "Steini","class": "skald","level": 58}}


function findChar(name, data) {
  for (let charGroup of Object.values(data)) {
    let found = Object.values(charGroup).find(char => char.name === name)
    if (found) return found
  }
}

console.log(findChar('Grop', data))
console.log(findChar('Brusi', data))

// will return undefined if the name is not there:
console.log(findChar('Mark', data))

If you were to modify the data structure to a simpler array format like this:

let data = {
    "olis characters": [{
        "name": "Farah",
        "class": "rogue",
        "level": 74
      },
      {
        "name": "Grop",
        "class": "paladin",
        "level": 31
      }
    ],
    "chris characters": [{
        "name": "Trygve",
        "class": "bard",
        "level": 28
      },
      // ...
    ]
 }

...you could eliminate one instance of using Object.values and directly apply the find method as shown below.

function findChar(name, data){
   for (let charGroup of Object.values(data)){
      let found = charGroup.find(char => char.name === name)
      if (found) return found
   }
 }

Answer 2

It appears that your data structure is a bit unusual. The presence of numeric keys in an object suggests it should be an array instead. However, you can still extract the desired information by utilizing the Object.values method.

let data = {"olis characters": {"0": {"name": "Farah","class": "rogue","level": 74},"1": {"name": "Grop","class": "paladin","level": 31},"2": {"name": "Skolmr","class": "druid","level": 85,}},"chris characters": {"0": {"name": "Trygve","class": "bard","level": 28},"1": {"name": "Brusi","class": "rogue","level": 10},"2": {"name": "Steini","class": "skald","level": 58}}


function findChar(name, data) {
  for (let charGroup of Object.values(data)) {
    let found = Object.values(charGroup).find(char => char.name === name)
    if (found) return found
  }
}

console.log(findChar('Grop', data))
console.log(findChar('Brusi', data))

// will return undefined if the name is not there:
console.log(findChar('Mark', data))

If you were to modify the data structure to a simpler array format like this:

let data = {
    "olis characters": [{
        "name": "Farah",
        "class": "rogue",
        "level": 74
      },
      {
        "name": "Grop",
        "class": "paladin",
        "level": 31
      }
    ],
    "chris characters": [{
        "name": "Trygve",
        "class": "bard",
        "level": 28
      },
      // ...
    ]
 }

...you could eliminate one instance of using Object.values and directly apply the find method as shown below.

function findChar(name, data){
   for (let charGroup of Object.values(data)){
      let found = charGroup.find(char => char.name === name)
      if (found) return found
   }
 }

Answer 3

Answer №2

Running a loop through an object like this can be challenging, suggesting that using an array of objects instead of an object of objects may be more suitable.

Here is a code snippet that might assist you:

const data = {
    "olis characters": {
        "0": {
            "name": "Farah",
            "class": "rogue",
            "level": 74
        },
        "1": {
            "name": "Grop",
            "class": "paladin",
            "level": 31
        },
        "2": {
            "name": "Skolmr",
            "class": "druid",
            "level": 85,
        }
    },
    "chris characters": {
        "0": {
            "name": "Trygve",
            "class": "bard",
            "level": 28
        },
        "1": {
            "name": "Brusi",
            "class": "rogue",
            "level": 10
        },
        "2": {
            "name": "Steini",
            "class": "skald",
            "level": 58
        }
    }
}


Object.keys(data).forEach(key => {
    if(findItemByName('Farah', data[key])){
        console.log(key)
    }
})

function findItemByName(name, item) {
    let result = false;
    Object.keys(item).forEach(objKey => {
        if (item[objKey].name == name) {
            result = true;
        }

    });

    return result;
}

Answer 4

Running a loop through an object like this can be challenging, suggesting that using an array of objects instead of an object of objects may be more suitable.

Here is a code snippet that might assist you:

const data = {
    "olis characters": {
        "0": {
            "name": "Farah",
            "class": "rogue",
            "level": 74
        },
        "1": {
            "name": "Grop",
            "class": "paladin",
            "level": 31
        },
        "2": {
            "name": "Skolmr",
            "class": "druid",
            "level": 85,
        }
    },
    "chris characters": {
        "0": {
            "name": "Trygve",
            "class": "bard",
            "level": 28
        },
        "1": {
            "name": "Brusi",
            "class": "rogue",
            "level": 10
        },
        "2": {
            "name": "Steini",
            "class": "skald",
            "level": 58
        }
    }
}


Object.keys(data).forEach(key => {
    if(findItemByName('Farah', data[key])){
        console.log(key)
    }
})

function findItemByName(name, item) {
    let result = false;
    Object.keys(item).forEach(objKey => {
        if (item[objKey].name == name) {
            result = true;
        }

    });

    return result;
}

analyzing a string against an embedded structure

Answer №1

Answer №2

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