The issue is that the JavaScript array becomes empty after being filled with values
Here is the code I used:
var browserdata = new Array();
// Fill the array with values
browserdata["qqq"] = "zzz";
browserdata["rrr"] = 1;
console.log(browserdata); // This displays an empty array
Expected output: { "qqq" => "zzz", "rrr" => 1 } Actual output: [] (empty array)
It is recommended to utilize the Object data type instead of an Array for this scenario. By using the object structure, you can assign properties and their corresponding values to achieve the desired output as shown in { "qqq" => "zzz", "zzz" => 1 }
var browserdata = {};
// Add values to the object
browserdata["qqq"] = "zzz";
browserdata["rrr"] = 1;
console.log(browserdata); Alternatively, you can assign properties at the time of declaring the object:
var browserdata = {
'qqq': 'zzz',
'rrr': 1
};
console.log(browserdata); When working with arrays, it's important to remember that they will never return empty as long as there is data present. In your code, the output will be [qqq: "zzz", rrr: 1]. If you prefer an output like { "qqq" => "zzz", "zzz" => 1 }, you should utilize objects. Objects serve as a way to group data together, similar to how you would organize information in a student array.
For instance, you can specify individual data within the object by using syntax like student['name'] = john; student['mark'] = 20;
Alternatively, you could define multiple sets of data within an array of students like so:
students = [{name: john, mark: 20}, {name: rick, mark: 20}]
Visit this link for more information on JavaScript arrays
This website provides insights into working with arrays in JavaScript
Using new Array() with a single argument as a number creates an array of specific length but without any items.
This approach is not commonly used due to the shorter syntax of using square brackets []. There is also a unique behavior associated with it, let's explore.
var arr = new Array(2); // Will this create an array of [2]?
console.log( arr[0] ); // It returns undefined as there are no elements.
console.log( arr.length ); // The length is 2
var browserdata = new Array();
browserdata[0] = "zzz";
browserdata[1] = 1;
console.log(browserdata);
console.log(browserdata.length);
I found that this method really worked well for me. Instead of using [], or new Array(), initializing with {} did the trick. Many thanks for sharing!
var webdata = {};
// Populating the object with data
webdata["aaa"] = "bbb";
webdata["ccc"] = 123;
console.log(webdata); By default, only the positive integer keys of the array object are visible, but all properties can still be accessed and viewed in the Google Chrome console.
var arr = []
arr[1] = 1
arr[-1] = -1
arr[.1] = .1
arr.a = 'a'
arr['b'] = 'b'
console.log( arr ) // [undefined, 1]
console.log( arr.b ) // "b"
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