Yet another error has been encountered: TypeError undefined is not a function

Hey everyone, I'm currently working on a JavaScript school project where I'm creating a dungeon. It may not be the best code out there, but hey, I'm still learning.

I'm encountering an error in the following code:

function damageFormula()
{
    var damage = myDamage(myWeapon); // The error is coming from this function
    var doDamage = Math.floor(0.085 * damage * myAttackLvl + (myLevelLvl/5) - (1+15*Math.random()));

    return doDamage;
};

The myDamage function looks like this:

function myDamage(myWeapon)
{
    switch(myWeapon)
    {
        case "Spike Sword":
            myDamage += 10;
            break;
        case "Magic Long Sword":
            myDamage += 20;
            break;
        default:
            myDamage += 3;
            break;
    }
    return myDamage;
};

The weapon variable is set as:

var myWeapon    = "Spike Sword";

And the myDamage variable is set as:

var myDamage    = 10;

Could someone please help me understand why I'm getting this error and possibly provide a solution?

If you require any additional information, feel free to ask me anything and I'll do my best to provide a clear answer.

Answer №1

Since the weapon myWeapon is set to Spike Sword, the following action is taken:

case "Spike Sword":
        myDamage += 10;
        break;

But keep in mind that myDamage() is a function, not just a number. Therefore, this confuses the JavaScript console! Instead of adding a number to myDamage, it turns into a string and appends "10" at the end of the string.

As a result, myDamage becomes a string value. However, when you call myDamage as a function inside damageFormula(), a potential TypeError could be triggered. In my experience,

I recommend initializing var damage = 0; and then incrementing it with damage += 10;, damage += 20;, and so on.

Answer №2

Watch out for your naming conventions -- you have chosen to call both a function and a variable myDamage. This can lead to confusion and inconsistencies within your code.

It is likely that you are declaring var myDamage elsewhere, which could result in it being null within the scope.

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