Working with integer loops in Javascript

Question

Working with integer loops in Javascript

As a beginner in learning JavaScript, I have been attempting to grasp the concepts by watching YouTube videos. Unfortunately, finding a solution for my current task has proven to be quite challenging.

The task at hand involves creating a program that prompts the user for a number and then displays all even numbers between 1 and the input provided by the user.

I am particularly struggling with understanding how selection statements and loops work together. Could someone kindly assist me in completing this task?

var inputNumber = prompt("Please enter a number");

var evenNumbers = [];

function findEvenNumbers(inputNumber) {
    for (var i = 1; i <= inputNumber; i++) {
        if(i % 2 === 0) {
            evenNumbers.push(i);
        }
    }
}

findEvenNumbers(inputNumber);
alert(evenNumbers);

javascript

Answer 1

Answer №1

To determine if a number is even, simply use the modulus operator in JavaScript. This operator gives you the remainder value of a division operation. If the remainder is equal to 0 when dividing by 2, then the number is even.

For more information on JavaScript operators, visit: http://www.w3schools.com/js/js_operators.asp

var userInput = prompt("Please enter a number");
var evens = [];

function findEvenNumbers(nums) {
  for (var i = 0; i <= nums; i++) {
    if (i % 2 === 0) {
      evens.push(i);
    }
  }
}

findEvenNumbers(userInput);
alert(evens);

Answer 2

To determine if a number is even, simply use the modulus operator in JavaScript. This operator gives you the remainder value of a division operation. If the remainder is equal to 0 when dividing by 2, then the number is even.

For more information on JavaScript operators, visit: http://www.w3schools.com/js/js_operators.asp

var userInput = prompt("Please enter a number");
var evens = [];

function findEvenNumbers(nums) {
  for (var i = 0; i <= nums; i++) {
    if (i % 2 === 0) {
      evens.push(i);
    }
  }
}

findEvenNumbers(userInput);
alert(evens);

Answer 3

Answer №2

To start, the code nums.length will provide you with the length of the string given by the user. You should then use

var nums = parseInt(prompt ("Please enter a number"));

. Assuming that the user inputs a valid number.

Next, implement a for loop:

for (var i=2; i<nums; i=i+2){
     alert (i);
}

1) As 1 is not an even number, it's best to begin at 2.

2) Since every second number is even, you can skip ahead directly to them (this is why we increment by 2).

3) To check if a number is even, employ the modulo function:

if(i%2 == 0)
    alert (i);

Answer 4

To start, the code nums.length will provide you with the length of the string given by the user. You should then use

var nums = parseInt(prompt ("Please enter a number"));

. Assuming that the user inputs a valid number.

Next, implement a for loop:

for (var i=2; i<nums; i=i+2){
     alert (i);
}

1) As 1 is not an even number, it's best to begin at 2.

2) Since every second number is even, you can skip ahead directly to them (this is why we increment by 2).

3) To check if a number is even, employ the modulo function:

if(i%2 == 0)
    alert (i);

Working with integer loops in Javascript

Answer №1

Answer №2

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