Why is my JavaScript sorting function not working after using push method?

Help me troubleshoot: Why aren't the results the same in IE9 and FF?

function TestArrayOperationsClick()
{
  function sortNums(a, b)
  {
    return a - b;
  }
  var array = [6, 4, 2, 8];
  console.log("Initial Array: " + array); 
  array.sort(sortNums);
  console.log("Sorted Array: " + array);
  array.push([1, 5, 10]);
  console.log("Updated Array: " + array);
  array.sort(sortNums);
  console.log("Re-Sorted Array: " + array);
}

Expected Output:

LOG: Initial Array: 6,4,2,8 

LOG: Sorted Array: 2,4,6,8 

LOG: Updated Array: 2,4,6,8,1,5,10 

LOG: Re-Sorted Array: 2,4,6,8,1,5,10 <- not sorted.

Answer №1

When using the array.push(...) method, remember to pass individual arguments instead of an array:

array.push(1, 5, 10);

By doing so, the final output will be:

Sort 2: 1,2,4,5,6,8,10 

Otherwise, if you pass an array, the result will be:

[2,4,6,8,[1,5,10]]

Although this may not be clearly visible when using console.log.

Edit: If you want to append an array of items, consider using .concat() method.

Answer №2

When using the .push() method, it does not combine arrays in the way you might expect. For example:

array.push([1, 5, 10]);

Instead of pushing the individual values, it actually pushes the second array itself, leading to the following result:

[ 2, 4, 6, 8, [ 1, 5, 10 ] ]

If you want to append one array onto another, you should use the .concat() method like this:

array = array.concat([1, 5, 10]);

Answer №3

When using the method array.push, it is advisable to pass individual arguments, like in this example:

array.push(1, 5, 10);

Alternatively, you can add the contents of one array into another array using the following method:

Array.prototype.push.apply(array, [1, 5, 10]);

By utilizing the apply() function, you are able to pass an array as an argument, as it converts the second argument (which should be an array) into individual arguments.

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