Whenever I execute the code, my if statement seems to interpret the conditions as true regardless of the actual values

let num = (Math.floor(Math.random() * 6 + 1))
console.log(num)

if (num === 6)
console.log('Wow, you hit the jackpot with a rarity of 1/6!')

The above code snippet generates a random number between 1 and 6, then prints "that was a 1/6 chance" if the number is exactly 6. However, even though it currently functions correctly and displays the message as intended, I would like it to only show the message when the number is 6.

Answer №1

Modify the if statement to

if (x === 6)

Revise your code as follows:

let x = (Math.floor(Math.random() * 6 + 1)); console.log(x);

if (x === 6) console.log('You hit the jackpot!');

Take note of the === in the if condition, ensuring a strict comparison between variables. By using ==, it could lead to unintentional assignment instead of comparison.

For further details, refer to: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Equivalence

Answer №2

a=10 is a declaration, which defines the value of a as 10, to verify equality use a===10

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