When the length of the Array is 100, the function Math.min.apply(Math, Array) will produce a

Question

When the length of the Array is 100, the function Math.min.apply(Math, Array) will produce a

Is it okay to use Math.min.apply when the length of the Array is 10?

getAllIndexes(arr, val) {
var indexes = [], i = -1;
while ((i = arr.indexOf(val, i+1)) != -1){
    indexes.push(i);
}
return indexes;
}

 arrayMinIndex(array) {
return this.getAllIndexes(array, Math.min.apply(Math,array));
}

https://i.sstatic.net/917Yz.png

However, when the Array's length is larger, for example 100, the value becomes NaN.

https://i.sstatic.net/Ibzlf.png

UPDATE!!!!

If I change the index names from 00,01,02,03 ... 99 to 0,1,2,3,4 ... 99, it works fine.

https://i.sstatic.net/vQx7H.png

In this scenario, I dynamically created the Array where the index name is a String. https://i.sstatic.net/BaPUJ.png

So, why does the index name cause a problem with Math.min?

javascript arrays min mathjax

Answer 1

Answer №1

It appears that in the process of creating the array, keys like '01', '02' are being used

This is different from index 1 and 2

Take a look at the following example:

const array1 = new Array();
const array2 = new Array();
const array3 = new Array();
array1[0] = 1;
array2['00'] = 2
array3[0] = 3
array3['00'] = 4

console.log(JSON.stringify(array1), typeof array1[0]);
console.log(JSON.stringify(array2), typeof array2[0]);
console.log(JSON.stringify(array3), typeof array3[0]);

Notice how array2[0] is undefined ... now if you try this:

const array = new Array();
array['00'] = 10;
array['01'] = 9;
array['02'] = 8;
array['03'] = 7;
array['04'] = 6;
array['05'] = 5;
array['06'] = 4;
array['07'] = 3;
array['08'] = 2;
array['09'] = 1;
array['10'] = 100;
console.log(array);

See all those undefined values before index 10

That's why Math.min results in NaN

Answer 2

It appears that in the process of creating the array, keys like '01', '02' are being used

This is different from index 1 and 2

Take a look at the following example:

const array1 = new Array();
const array2 = new Array();
const array3 = new Array();
array1[0] = 1;
array2['00'] = 2
array3[0] = 3
array3['00'] = 4

console.log(JSON.stringify(array1), typeof array1[0]);
console.log(JSON.stringify(array2), typeof array2[0]);
console.log(JSON.stringify(array3), typeof array3[0]);

Notice how array2[0] is undefined ... now if you try this:

const array = new Array();
array['00'] = 10;
array['01'] = 9;
array['02'] = 8;
array['03'] = 7;
array['04'] = 6;
array['05'] = 5;
array['06'] = 4;
array['07'] = 3;
array['08'] = 2;
array['09'] = 1;
array['10'] = 100;
console.log(array);

See all those undefined values before index 10

That's why Math.min results in NaN

Answer 3

Answer №2

Your initial filter for non-numeric values involves checking if your array contains any non-numeric values.

var filteredArr = arr.filter(function (item) {
  return !isNaN(item);
});

To find the minimum value in the array, you can use:

Math.min.apply(Math,array.filter(n => !isNaN(n)))

Answer 4

Your initial filter for non-numeric values involves checking if your array contains any non-numeric values.

var filteredArr = arr.filter(function (item) {
  return !isNaN(item);
});

To find the minimum value in the array, you can use:

Math.min.apply(Math,array.filter(n => !isNaN(n)))

When the length of the Array is 100, the function Math.min.apply(Math, Array) will produce a

Answer №1

Answer №2

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