At its current state, the y variable would not be defined.
This is because you are declaring it within an if statement and trying to use console.log outside of that scope where it has not been declared. For more information on JavaScript scopes, check out this informative thread.
If you encounter issues with the taxableIncome being undefined, there are two ways to address the problem of y not being defined:
If y is only used within the if block, it's acceptable to declare it there; however, any actions taken on it (like console.log) must also be contained within the same if block. Here's how you can adjust your code:
let taxableIncome = 80000;
if(taxableIncome >37000 && taxableIncome <80001) {
const y = taxableIncome - 37000;
console.log(y)
// any additional operations involving y should go here
}
console.log(taxableIncome);
A more flexible solution might be to declare y before the if statement. Since a value is assigned later on, y should be declared as let instead of const:
let taxableIncome = 80000;
let y;
if(taxableIncome >37000 && taxableIncome <80001) {
y = taxableIncome - 37000;
}
console.log(y);
console.log(taxableIncome);
Additionally, note that the semicolon after the if statement is unnecessary.