What kind of functionality does the spread syntax showcase?

After exploring the MDN documentation regarding spread syntax, an intriguing example caught my attention:

function myFunction(v, w, x, y, z) {
  console.log(v);
  console.log(w);
  console.log(x);
  console.log(y);
  console.log(z);
}

const args = [0, 1];
myFunction(-1, ...args, 2, ...[3]);

Upon examining the usage of ...args, it became clear that it copies the values from each item within args (0, 1).

However, the mystery surrounding ...[3] lingered. Despite its resolution to 3 when logged, I found myself deeply pondering its function and purpose. What exactly is ...[3]? How does it operate, and why does it ultimately result in 3?

Answer №1

equivalent:

const myNum = [3]

console.log( ...myNum ) // ->  3
console.log( ...[3] ) // ->  3

Answer №2

When dealing with ...[3], it serves as a visual demonstration of how the spread operator behaves when applied to an array containing only one element - in this case, returning that single element.

To clarify further, the distinction between [3] and ...[3] lies in their composition: the former being a 3-element array while the latter simply represents the value 3 on its own.

An illustration might help:

console.log(...[3,4,5])  // outputs 3,4,5
console.log(...[3,4]) // outputs 3,4
console.log(...[3]) // outputs 3
console.log(3) // outputs 3 (same as previous example)
console.log([3]) // outputs an array consisting solely of the number 3

Answer №3

...[3] represents the number 3 being stored in an array and immediately spread. The use of the array operator [] takes precedence over the spread-operator. In this particular scenario, it would be simpler to directly include 3 instead of packing and unpacking it afterwards.

Situations may arise where you need to append a single element to your array based on certain conditions. For instance:

const myArray = [
  1,
  2,
  ...(shallAddThree ? [3] : []),
  4
];

Depending on whether shallAddThree is truthy or falsy, the result could vary. Spreading an empty array has no effect on the final array. This can be visualized by the following two scenarios:

  1. If shallAddThree is true
const myArray = [
  1,
  2,
  ...[3], // parentheses not needed here
  4
];
  1. If shallAddThree is false
const myArray = [
  1,
  2,
  ...[], // parentheses not needed here
  4
];

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