What is the solution for excluding 0s in my javascript code?

Question

What is the solution for excluding 0s in my javascript code?

I am working on a code to calculate the average of four numbers entered by the user, but I want to exclude zeros from the calculation. Currently, the code successfully excludes one zero, but I am struggling to exclude multiple zeros. My initial approach was to remove any number containing a zero, so that the average is only calculated based on non-zero numbers. Here is the code snippet:

var num1 = parseInt(prompt("Enter the first number:"), 10);
var num2 = parseInt(prompt("Enter the second number:"), 10);
var num3 = parseInt(prompt("Enter the third number:"), 10);
var num4 = parseInt(prompt("Enter the fourth number:"), 10);
  
if (num1 == 0){
    document.getElementById("output").textContent = ((num2 + num3 + num4) / 3);  
}
if (num2 == 0){
    document.getElementById("output").textContent = ((num1 + num3 + num4) / 3);  
}
if (num3 == 0){
    document.getElementById("output").textContent = ((num1 + num2 + num4) / 3);  
}
if (num4 == 0){
    document.getElementById("output").textContent = ((num1 + num2 + num3) / 3);  
}
else {
    document.getElementById("output").textContent = ((num1 + num2 + num3 + num4) / 4);  
}

javascript average

Answer 1

Answer №1

Ponder over your current train of thought.

You devised a code snippet that calculates the average of three numbers if one of the four numbers is zero. However, you've now realized that it fails to work when two of the four numbers are zeroes. How many additional if-else statements would you need to add to account for this scenario? Now, envision a situation where three of the numbers are zeroes.

This issue seems straightforward as it involves only four inputs. But imagine extending this to 100 inputs, aiming to calculate the averages of all non-zero integers from the inputs.

A more scalable solution would be to create a code that focuses solely on and averages the non-zero integers, regardless of the number of inputs. Consider the following approach:

let num1 = 3; //assumed to be equivalent to var num1 = parseInt(prompt("first number: "),10);
let num2 = 4; //assumed to be equivalent to var num2 = parseInt(prompt("second number: "),10);
let num3 = 0; //assumed to be equivalent to var num3 = parseInt(prompt("third number: "),10);
let num4 = 0; //assumed to be equivalent to var num4 = parseInt(prompt("fourth number: "),10);

const numbers = [num1, num2, num3, num4]

function avgNonZeroValues(nums){
  const nonZeros = nums.filter(number => number !== 0);
  const avgOfNonZeros = nonZeros.reduce(
    (accumulator, currentValue) => accumulator + currentValue,
    0
  )/nonZeros.length;
  
  return avgOfNonZeros;
}

console.log(avgNonZeroValues(numbers));

It's important to familiarize yourself with two essential functions:

reduce()

Reduce is a powerful method for iterating through a list/array and performing operations on it. By specifying an initial value (0 in our case) and the actions to be taken on each element, we can, in this scenario, obtain the sum of all numbers in the array.

filter()

As the name suggests, the filter function takes an array and a condition, removes the elements that don't meet the criteria, and returns a new array with only the elements that satisfy the condition. In this case, we are using it to eliminate all zeros from the array.

Providing an array of any length containing numbers to the avgNonZeroValues function will result in the removal of all zeros before calculating the average of the remaining numbers.

Answer 2

Ponder over your current train of thought.

You devised a code snippet that calculates the average of three numbers if one of the four numbers is zero. However, you've now realized that it fails to work when two of the four numbers are zeroes. How many additional if-else statements would you need to add to account for this scenario? Now, envision a situation where three of the numbers are zeroes.

This issue seems straightforward as it involves only four inputs. But imagine extending this to 100 inputs, aiming to calculate the averages of all non-zero integers from the inputs.

A more scalable solution would be to create a code that focuses solely on and averages the non-zero integers, regardless of the number of inputs. Consider the following approach:

let num1 = 3; //assumed to be equivalent to var num1 = parseInt(prompt("first number: "),10);
let num2 = 4; //assumed to be equivalent to var num2 = parseInt(prompt("second number: "),10);
let num3 = 0; //assumed to be equivalent to var num3 = parseInt(prompt("third number: "),10);
let num4 = 0; //assumed to be equivalent to var num4 = parseInt(prompt("fourth number: "),10);

const numbers = [num1, num2, num3, num4]

function avgNonZeroValues(nums){
  const nonZeros = nums.filter(number => number !== 0);
  const avgOfNonZeros = nonZeros.reduce(
    (accumulator, currentValue) => accumulator + currentValue,
    0
  )/nonZeros.length;
  
  return avgOfNonZeros;
}

console.log(avgNonZeroValues(numbers));

It's important to familiarize yourself with two essential functions:

reduce()

Reduce is a powerful method for iterating through a list/array and performing operations on it. By specifying an initial value (0 in our case) and the actions to be taken on each element, we can, in this scenario, obtain the sum of all numbers in the array.

filter()

As the name suggests, the filter function takes an array and a condition, removes the elements that don't meet the criteria, and returns a new array with only the elements that satisfy the condition. In this case, we are using it to eliminate all zeros from the array.

Providing an array of any length containing numbers to the avgNonZeroValues function will result in the removal of all zeros before calculating the average of the remaining numbers.

Answer 3

Answer №2

When we refactor this code to utilize arrays, it becomes much easier to leverage array functions for filtering and transforming numbers.

const prompts = ["first", "second", "third", "fourth"];

const values = prompts
  .map(p => parseInt(prompt(`${p} number: `),10))
  .filter(v => v !== 0);

const total = values.reduce((acc, val) => acc + val, 0);
const avg = total/values.length;

console.log(total, avg);

Answer 4

When we refactor this code to utilize arrays, it becomes much easier to leverage array functions for filtering and transforming numbers.

const prompts = ["first", "second", "third", "fourth"];

const values = prompts
  .map(p => parseInt(prompt(`${p} number: `),10))
  .filter(v => v !== 0);

const total = values.reduce((acc, val) => acc + val, 0);
const avg = total/values.length;

console.log(total, avg);

What is the solution for excluding 0s in my javascript code?

Answer №1

Answer №2

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