Answering a related question about object constructors, what is the intention behind passing an argument to the constructor of objects and using it in this specific manner?
function makeFoo(a, b) {
var foo = Object.create(Foo.prototype);
var result = Foo.apply(foo, arguments);
return Object(result) === result ? result : foo;
}
The Object constructor will only return its parameter if it is already an object. Therefore, your code is simply checking to make sure that the value of result is indeed an object.
In the specific function referenced in another question, the purpose is to handle a scenario where the "Foo" constructor may attempt to return something other than an object (e.g., a string) when called without using the new keyword. When you invoke a constructor with new, any non-object return value will be disregarded, and the result will be the newly constructed object.
Object constructor will simply return the reference without creating a new object, resulting in them being strictly equal (===) to the input parameter ("result"). However, if they are not strictly equal, it suggests that the constructor behaved unexpectedly, so the created "foo" instance will be returned instead.
It is worth mentioning that the other question described this approach as a "hack".
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