When working with AngularJS, the $q.defer() promise object has the ability to receive multiple notify callbacks without overwriting previous ones.
var def = $q.defer();
def.promise.then(null, null, callback1);
def.promise.then(null, null, callback2);
If you need to remove (unregister) a specific callback, such as callback2, how can this be achieved?
Check out this live example:
Upon inspecting the source code for $q, it is evident that:
then: function(onFulfilled, onRejected, progressBack) {
var result = new Deferred();
this.$$state.pending = this.$$state.pending || [];
this.$$state.pending.push([result, onFulfilled, onRejected, progressBack]);
if (this.$$state.status > 0) scheduleProcessQueue(this.$$state);
return result.promise;
}
There does not seem to be a specific identifier within the $$state.pending stack that can directly remove an anonymous callback.
I have not personally tested this method, but clearing the pending stack with def.$$state.pending = []; could potentially work. Then, you can selectively reassign only the desired def.then() callbacks.
Using promises can help manage a series of asynchronous tasks seamlessly. Once a step in the sequence is established, it's not easily reversible.
If I understand correctly, you're attempting to set a step with callback2 and then remove it. Instead, consider assigning callback2 only if specific conditions are met, like this:
var notifCallback;
if (true) {
notifCallback = function(notif) {
console.log('notify 1', notif);
};
} else {
notifCallback = function(notif) {
console.log('notify 2', notif);
};
}
def.promise.then(null, null, notifCallback);
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