Can we develop a function called wizard() that can transform the following array:
[{a:1}, {b:2}, wizard(), {e:5}]
to the desired output:
[{a:1}, {b:2}, {c:3}, {d:4}, {e:5}]
Can we develop a function called wizard() that can transform the following array:
[{a:1}, {b:2}, wizard(), {e:5}]
to the desired output:
[{a:1}, {b:2}, {c:3}, {d:4}, {e:5}]
Not using that specific syntax, it's not possible. You can come very close in ES2015, but achieving exact identity is not possible (in ES5 and earlier versions, it's even more challenging).
In ES2015 ("ES6") and beyond, you have the ability to make magic return any iterable (such as an array) and utilize it with spread notation:
let a = [{a:1}, {b:2}, ...magic(), {e:5}];
// Spread notation ----^^^
For instance:
// REQUIRES SUPPORT FOR ES2015 OR HIGHER
function magic() {
return [{c: 3}, {d: 4}];
}
let array = [{a:1}, {b:2}, ...magic(), {e:5}];
console.log(array);In pre-ES6 languages like ES5, you can configure magic to return an array and employ concat:
var array = [{a:1}, {b:2}].concat(magic()).concat([{e:5}]);
For example:
function magic() {
return [{c: 3}, {d: 4}];
}
var array = [{a:1}, {b:2}].concat(magic()).concat([{e:5}]);
console.log(array);This method may not be super efficient since it generates and discards temporary arrays, but in most cases, that level of optimization isn't critical.
Unfortunately, it is not possible to use magic with arrays as magic does not understand how to work with them directly. One alternative could be to pass the array as a parameter and have the function return a modified version of it.
var arr = [{x:3}, {y:7},{z:1}];
arr = doMagic(arr); // invoke the magic
Alternatively, you could also extend the Array.prototype to include a magic method.
Array.prototype.magic = function(){
// perform your magic here
};
var arr = [{x:3}, {y:7},{z:1}].magic();
@Johannes Merz is absolutely correct. It is impossible to perform this task while the array is still being constructed. However, what if we were to shift the operation to an asynchronous or delayed timeline? In that case, it might just work. Let's take a look...
function performMagic(){
setTimeout(_ => {
var index = arr.indexOf(arguments.callee.name);
arr.splice(index, 1);
arr.splice(index, 0, {c:3}, {d:4});
console.log(arr);
}, 0);
return arguments.callee.name;
}
var arr = [{a:1}, {b:2}, performMagic(), {e:5}];
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