What is the correct value for X to make this condition valid?
// Your code goes here
if (x == 1 && x === 2) {
console.log('Success!');
}
What is the correct value for X to make this condition valid?
// Your code goes here
if (x == 1 && x === 2) {
console.log('Success!');
}
To define Y, use the following code:
Object.defineProperty(window,'y',{
get: function() {
this.__temp = this.__temp || 4;
this.__temp = 6-this.__temp;
return this.__temp;
}
});
After that:
if( y == 3 && y === 4)
COULD potentially work. Example
Check out the code snippet below for an interesting JavaScript puzzle (Demo here):
x = {};
x.valueOf = function (){
x = 2; // this is crucial
return 1;
};
if (x == 1 && x === 2) {
console.log('Success !!!');
}
Explanation:
The code first checks if x == 1, which triggers the valueOf function and returns 1, making it true. However, while evaluating this, x is changed to 2. This change makes the subsequent check on x === 2 also pass.
PS: Although this may not have real-world applications, it offers insights into JavaScript's inner workings - making it a valuable learning exercise :)
It is logically incorrect to assign the value of both 1 and 2 to variable X simultaneously.
x === 2 is used to check if the value of x is exactly equal to 2, making it impossible for 2 to simultaneously be 1.
The correct approach would be:
if (x && x === 2) { ... }
(or through method overloading, as shown in @Niet the Dark Absol's response, which isn't a straightforward scenario)
By utilizing the === (identity) operator, achieving this may seem impossible; however, it is feasible to create an object that equates to both 1 and 2 using the == operator simultaneously:
x = { valueOf: function() { return this.foo ? 2 : this.foo = 1 } }
console.log(x == 1 && x == 2) // true
The "valueOf" method in JavaScript is automatically invoked when converting or comparing an object to a number.
It goes without saying that this exercise holds no practical significance.
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