What is the most efficient method for converting an array-like object into an actual array?

Imagine a scenario where we have the following:

var obj = {"1": 1, "2": 2, "5": 5};

Now, suppose I wish to transform it into an array that looks like this:

var obj = []; obj[1] = 1; obj[2] = 2; obj[5] = 5;

Is there a way to achieve this transformation?

Answer №1

Give this a shot:

let obj = { ... }; // your object
let objArr = [];
for (let key in obj) {
    if (parseInt(key) == key) {
        objArr[parseInt(key)] = obj[key];
    }
}

Keep in mind that only numeric keys will be accepted.

Answer №2

If you possess a valid length property, handling it is quite simple:

var o = {"1": 1, "2": 2, "5": 5, 'length' : 6};
o = Array.prototype.slice.call(o); // [undefined, 1, 2, undefined, undefined, 5]

In case the length property is absent, you can calculate it as follows:

var o = {"1": 1, "2": 2, "5": 5};    

o.length = Object.keys(o).reduce(function(max,key){
  return isNaN(key) ? max : Math.max(max, +key);
},-1) + 1;

o = Array.prototype.slice.call(o); // [undefined, 1, 2, undefined, undefined, 5]

It's important to keep in mind that when accessing an object's property, it gets automatically converted to a string. This means that the following will work for your instance, regardless of whether o is not an array:

var o = {"1": 1, "2": 2, "5": 5};
o[1] // 1
o[2] // 2
o[5] // 5
o[0] // undefined

Answer №3

Avoid the mistake of assuming the maximum index value, 1. Uncertainty exists regarding the upper limit of the index. 2. Gaps could exist in the array, resulting in null values for some indexes.

Instead, convert the index number to a string and search for it within the same object.

 var obj = {"1": 1, "2": 2, "5": 5};
 var idx = 5;
 obj[idx.toString()]  // returns 5

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