Regarding the question title, I have implemented the following:
Array.prototype.containsAny = function (otherArray) {
for (let i = 0; i < otherArray.length; i++)
if (this.includes(otherArray[i]))
return true;
return false;
};
let set1 = [3, 5, 9];
let set2 = [4, 5];
set1.containsAny(set2);
Is there an alternative approach that may be more efficient?
If you want to check for elements that exist in two arrays, you can utilize the some and includes methods.
let array1 = [3, 5, 9];
let array2 = [4, 5];
function checkIntersection(array1, array2) {
return array1.some(element => array2.includes(element));
}
console.log(checkIntersection(array1, array2));
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