I need assistance with the following URL:
https://192.168.0.10/users/#!/user-profile/20When I use $location.host, it returns 192.168.0.10
However, I only want to extract
https://192.168.0.10
What is the best way to achieve this?
I need assistance with the following URL:
https://192.168.0.10/users/#!/user-profile/20When I use $location.host, it returns 192.168.0.10
However, I only want to extract
https://192.168.0.10
What is the best way to achieve this?
Here's a useful tip:-
let getProtocol = $location.protocol();
let getHost = $location.host();
let combineURL = getProtocol + '://' + getHost;
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