What is the method to develop a variable set at the utmost minimum value?

I have developed an algorithm designed to identify the highest value within each subarray and then push that value onto a separate array called 'final'.

As part of this process, I aim to assign the variable 'value' the lowest possible number so that negative numbers can be considered greater than 'value'.

function largestOfFour(arr) {
  var final=[];
  arr.map(sub => {
    let value = 0; // Starting point
    sub.map(num => {
      if(num>value){value=num};
    })
    final.push(value)
  })
  return final;
}
console.log(largestOfFour([[17, 23, 25, 12], [25, 7, 34, 48], [4, -10, 18, 21], [-72, -3, -17, -10]]));

In the given example, the last subarray produces a result of 0 since none of its numbers surpass the initial value assigned to 'value', which is set at 0.

My goal is for the output to reflect '-3', as it represents the highest number within the subarray.

javascriptarraysalgorithm

Answer №1

If you're searching for the maximum value in each array, this code snippet could be helpful.

You can utilize Array#map, Math#max, and spread syntax to achieve this task efficiently.

const data = [[17, 23, 25, 12], [25, 7, 34, 48], [4, -10, 18, 21], [-72, -3, -17, -10]];

const res = data.map(arr=>Math.max(...arr));

console.log(res);

Answer №2

To assign the value of Number.NEGATIVE_INFINITY, you can simply set the value. However, I would suggest using reduce instead of map in your inner function for better efficiency. By doing this, the inner loop will start with sub[0] as an initial value rather than relying on any placeholder.

function largestOfFour(arr) {
  var final = arr.map(sub => sub.reduce((num, value) => Math.max(num, value)));
  return final;
}
console.log(largestOfFour([
  [17, 23, 25, 12],
  [25, 7, 34, 48],
  [4, -10, 18, 21],
  [-72, -3, -17, -10]
]));

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