In my array, all = [2,3,4,12, 55,33], there is a sub-array named ar1 = [12, 55, 33] starting from the value 12.
If I remove a value from all that is present in ar1 (e.g. 12), how can I determine the index of this value in ar1 (0 for 12) so I can also remove it from ar1?
Edit: The elements in my actual array are objects; I have used numbers here for illustration purposes.
When dealing with an array containing objects, it is important to assign each object a unique identifier using the id property. This will allow you to easily filter and manipulate individual objects within the array based on their identifiers.
To find the index of a specific object in the array, you can utilize the Array.findIndex method as demonstrated in the following example:
const arr = [{ id: "abc" }, { id: "def" }];
arr.findIndex (itm => itm.id === "def") // Returns 1
If assigning an id is not possible, an alternative approach would involve performing a deep object comparison. While this method may not be entirely accurate, it is still effective in many cases. You can achieve this by implementing your own comparison logic or utilizing libraries like Lodash's _.isEqual.
In order to remove an element from the first array and then subsequently remove it from the second array, you can utilize the Array#splice() method to eliminate the element in question. Afterwards, you can locate its position using index within the array by employing Array#findIndex(), and finally delete it from the secondary array.
var [removed] = all.splice(3, 1);
var index = ar1.findIndex(el => el.val == removed.val);
if (index !== -1) {
ar1.splice(index, 1);
}
Demo:
var all = [{ val: 2}, { val: 3}, {val: 4}, {val: 12}, {val: 55
}, {val: 33}],
ar1 = [{val: 12}, {val: 55}, {val: 33}];
var [removed] = all.splice(3, 1);
console.log(removed);
var index = ar1.findIndex(el => el.val == removed.val);
if (index !== -1) {
ar1.splice(index, 1);
}
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