What is the method for incorporating a counter variable into a variable's name?

Question

What is the method for incorporating a counter variable into a variable's name?

Here's my code, which I know is very inefficient:


var slider1 = new Slider("#survey1", {
    precision: 2,
    value: 5
})
var slider2 = new Slider("#survey2", {
    precision: 2,
    value: 5
})
var slider3 = new Slider("#survey3", {
    precision: 2,
    value: 5
})
var slider4 = new Slider("#survey4", {
    precision: 2,
    value: 5
})
var slider5 = new Slider("#survey5", {
    precision: 2,
    value: 5
})

I know this can be done more efficiently. It should continue up to "#survey13" but for the sake of saving space, I skipped those details. Perhaps using a for loop would make it cleaner? How could I incorporate a counter into the variable name and referenced ID?

javascript

Answer 1

Answer №1

Here is how you can achieve the desired result:

let allSliders = [];
for (let index = 1; index <= 13; index++) {
    let slider = new Slider("#survey" + index, {
        precision: 2,
        value: 5
    });
    allSliders.push(slider);
}

Now, slider1 corresponds to allSliders[0], slider2 corresponds to allSliders[1], and so forth.

Answer 2

Here is how you can achieve the desired result:

let allSliders = [];
for (let index = 1; index <= 13; index++) {
    let slider = new Slider("#survey" + index, {
        precision: 2,
        value: 5
    });
    allSliders.push(slider);
}

Now, slider1 corresponds to allSliders[0], slider2 corresponds to allSliders[1], and so forth.

Answer 3

Answer №2

To create a slider for each item, you can utilize a for loop. Simply add the slider instance to an array for later use.

var options = {
    precision: 2,
    value: 5
};
var slider = [];

for (var i = 1; i <= 13; i++) {
    slider.push(new Slider("#survey" + i, options));
}

If the plugin supports multiple selectors

var slider = new Slider("#survey1, #survey2, #survey3 ...", {
    precision: 2,
    value: 5
});

Alternatively, you can assign a common class to all elements and use that class to assign sliders. This approach is dependent on how Slider is defined.

var slider = new Slider(".slider", {
    precision: 2,
    value: 5
});

Answer 4

To create a slider for each item, you can utilize a for loop. Simply add the slider instance to an array for later use.

var options = {
    precision: 2,
    value: 5
};
var slider = [];

for (var i = 1; i <= 13; i++) {
    slider.push(new Slider("#survey" + i, options));
}

If the plugin supports multiple selectors

var slider = new Slider("#survey1, #survey2, #survey3 ...", {
    precision: 2,
    value: 5
});

Alternatively, you can assign a common class to all elements and use that class to assign sliders. This approach is dependent on how Slider is defined.

var slider = new Slider(".slider", {
    precision: 2,
    value: 5
});

Answer 5

Answer №3

Experiment using arrays:

let sliders = [];
let settings = {
   precision: 2,
   value: 5
};
for (let index = 1; index <= 13; index++)
   sliders[index] = new Slider("#survey" + index, settings);

If you prefer named variables, consider using objects:

let sliders = {};
let settings = {
   precision: 2,
   value: 5
};
for (let index = 1; index <= 13; index++)
   sliders['survey' + index] = new Slider("#survey" + index, settings);

Answer 6

Experiment using arrays:

let sliders = [];
let settings = {
   precision: 2,
   value: 5
};
for (let index = 1; index <= 13; index++)
   sliders[index] = new Slider("#survey" + index, settings);

If you prefer named variables, consider using objects:

let sliders = {};
let settings = {
   precision: 2,
   value: 5
};
for (let index = 1; index <= 13; index++)
   sliders['survey' + index] = new Slider("#survey" + index, settings);

Answer 7

Answer №4

Instead of utilizing an array like others have suggested, a more effective approach would be to employ an object:

var identifier = 'poll',
    sliders = {},
    count = 9;

do {
  sliders[identifier + count] = new Slider('#' + identifier + count, {
    precision: 2,
    value: 5
  });
} while(count--);

Subsequently, you can access the object you've generated: sliders.poll1, sliders.poll2, and so on!

Answer 8

Instead of utilizing an array like others have suggested, a more effective approach would be to employ an object:

var identifier = 'poll',
    sliders = {},
    count = 9;

do {
  sliders[identifier + count] = new Slider('#' + identifier + count, {
    precision: 2,
    value: 5
  });
} while(count--);

Subsequently, you can access the object you've generated: sliders.poll1, sliders.poll2, and so on!

Answer 9

Answer №5

It's not possible to alter the referenced id, however, you have the option of generating it with PHP prior to loading the page.

<?php
$i = 0;
for ($i; $i < n; $i++) {
    echo 'var slider = new Slider("#survey' + $i + '", {
        precision: 2,
        value: 5
    })';
}
?>

Answer 10

It's not possible to alter the referenced id, however, you have the option of generating it with PHP prior to loading the page.

<?php
$i = 0;
for ($i; $i < n; $i++) {
    echo 'var slider = new Slider("#survey' + $i + '", {
        precision: 2,
        value: 5
    })';
}
?>

What is the method for incorporating a counter variable into a variable's name?

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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