What is the method for acquiring the final shape of a particular type?

Is there a way to locate the last path or circle in a paper so that I can perform additional calculations to add more elements? Currently, calling paper.bottom only retrieves the last element. Is it possible to access shapes of specific types, like bottom.path, bottom.circle, or even traverse to find the n'th child?

I'm trying to avoid using jQuery selectors because I am unable to retrieve any properties from them.

Here is an example of a paper with shapes:

var paper = Raphael('paper',500,500);
var c1 = paper.circle(100,100,50)
var p1 = paper.path("M10 20l70 0")
var c2 = paper.circle(200,100,50)

Answer №1

Looking for the lowest element will give you the element at the very bottom along the Z axis, which may not be the desired outcome. Imagine a scenario where the Z order of elements changes, such as by using Element.toBack(), this could invalidate your search.

Instead, consider a more semantic approach by iterating through the elements array and finding the last element of a specific type (like a circle).

Raphaël also provides the option to extend the default set of functions, allowing you to add a function to the paper element specifically for this purpose. Below is an example of a function that retrieves the last element of a given type from the paper, or false if no such element is found:

Raphael.fn.last = function(type) {
    var element;
    this.forEach(function(el) {
        if (el.type == type) {
            element = el;
        }
    });
    return element || !!element;
};

Make sure to add this function before creating any paper elements. Then, you can simply call it with the desired element type:

var r = Raphael(paper, '100%', '100%');
// ...
// add elements etcetera
// ...
var lastCircle = r.last('circle');

Keep in mind that this approach may be resource-intensive if the paper contains many elements. However, the main goal is to introduce the concept of extending functionality and stimulate your thought process. Feel free to optimize the function for better efficiency.


See Live Demo

Answer №2

When it comes to navigating to the nth child element, the process is quite straightforward. Simply place your paths in a set, and they will be indexed just like any regular array. This allows you to easily reference any specific element within the set and access its properties:

var myPaper = Raphael('container', '800', '600');

myPaper.setStart();
var circ1 = myPaper.circle(50, 50, 40);
var circ2 = myPaper.circle(150, 50, 40);
var circ3 = myPaper.circle(250, 50, 40);
var circ4 = myPaper.circle(350, 50, 40);
var allCircles = myPaper.setFinish();

allCircles[2].attr({fill: "blue"});

http://jsfiddle.net/eE7xS/

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