What is the correct RegEx pattern I should use to properly match the provided test case without including the ending period?

Regular Expression:

/@([\S]*?(?=\s)(?!\. ))/g

Given String:

'this string has @var.thing.me two strings to be @var. replaced'.replace(/@([\S]*?(?=\s)(?!\. ))/g,function(){return '7';})

Expected Result:

'this string has 7 two strings to be 7. replaced'

If you'd like to improve it, I am attempting to match Razor Html Encoded Expressions, but please note the condition of not matching an ending period followed by a space. The example above demonstrates this with the first capturing as @var.thing.me and the second (shorter) one as just @var.

javascriptregex

Answer №1

Give this regular expression a shot:

var sentence = 'this string has @var.thing.me two strings to be @var. replaced';
sentence.replace(/@[a-z][a-z.]+[a-z]/gi, function(){
  return '7';
});

The regex pattern @[a-z]([a-z.]+[a-z])* looks for an @, followed by a letter (no dot allowed right after @), then a series of letters or dots and another letter at the end.

The i modifier enables case-insensitivity in the regex.

Answer №2

Your pattern may need some adjustments to make it more accurate. It seems to be capturing too much in certain scenarios. The issue lies in the lookahead conditions, which are not providing the desired specificity. You can refine your pattern by considering the following modification:

/@([\S]*?)(?=[.]?\s)/g

This updated pattern will target the @something substring effectively, irrespective of whether it is followed by a space or a dot and a space. Testing this revised pattern in a browser console showed promising results:

> 'this sample text has @var.words.here two instances with different patterns. validate'.replace(/@([\S]*?)(?=[.]?\s)/g,function(){return '7';})
"this sample text has 7 two strings to be 7. replaced"

Answer №3

Give this a try

@((?!\. )\S)+

Check it out here on regex101

This code snippet is designed to match a "@" symbol followed by non-whitespace characters (\S), but it will only match the next non-whitespace character if it is not a dot followed by a space. This is achieved using a negative lookahead assertion (?!\. ) before the \S.

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