What is the best way to utilize a closure in order to continuously log each element within an array using a SetInterval in JavaScript

function displayValues(inputValues) {
    for (var counter = 0; counter < inputValues.length; counter++) {     
       setInterval(function() {
          console.log('The item ' + counter + ' has value ' + inputValues[counter]) //Currently only logs length of array
      }, 500)
    }
}
var arrayOfElements = ['a', 'b', 'c', 'd'];
displayValues(arrayOfElements)

I wrapped the SetInterval in a separate function that currently displays index 0 and its corresponding value 'a', however, I am unable to capture the values for the rest of the items. Here is my revised code below. Am I on the right track?

function showValues(valuesArray) {

  function getDisplay(){
    return setInterval(function() {
          console.log('The item ' + i + ' has value ' + values[i])
      }, 500)
  }
    for (var i = 0; i < valuesArray.length; i++) {     
       return getDisplay()
    }
}

Answer №1

This method allows for looping smoothly, as the variable is declared outside of the setInterval function and begins completing loops every 500ms instead of waiting (asynchronously). This ensures that the length of the array is always taken into account using i++ until i < value.length.

function showValues(values) {
  for (var i = 0; i < values.length; i++) {
    (function(j) {
      setInterval(function() {
        console.log('The item ' + j + ' has the value ' + values[j]);
      }, 500);
    })(i);
  }
}
var array = ['a', 'b', 'c', 'd'];
showValues(array)

Let's break it down further

function displayData(values) {
  function getValues(j) {
    setInterval(function() {
      console.log('The item ' + j + ' contains the value ' + values[j]);
    }, 500);
  }
  for (var i = 0; i < values.length; i++) {
    getValues(i);
  }
}

var items = ['a', 'b', 'c', 'd'];
displayData(items);

Both snippets essentially achieve the same outcome. The second snippet introduces an external function called getValues, while in the first snippet it remains an anonymous function.

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