What is the best way to streamline the if statement in JavaScript?

Here is the given code snippet:

public noArtistBeingEdited(): boolean {
    if (this.isFirstNameBeingEdited()) {
        return false;
    }
    if (this.isLastNameBeingEditable()) {
        return false;
    }
    return true;
}

What are some ways to make this code simpler?

Answer №1

To check if an artist is not being edited, use the OR operator (||):

public isArtistNotBeingEdited(): boolean {
    if (!this.isFirstNameBeingEdited() || !this.isLastNameBeingEditable()) {
        return true;
    }
    return false;
}

Answer №2

To simplify the process, start by combining the two statements into one for easier understanding. If either the first statement or the last statement is true, then the overall result will be false.

public noArtistBeingEdited(): boolean {
    if (this.isFirstNameBeingEdited() || this.isLastNameBeingEditable()) {
        return false;
    }
    return true;
}

You can consolidate

this.isFirstNameBeingEdited() || this.isLastNameBeingEditable()
inside brackets to treat it as a single statement.

(this.isFirstNameBeingEdited() || this.isLastNameBeingEditable())
=== false

If you negate the entire statement, it will result in true:

!(this.isFirstNameBeingEdited() || this.isLastNameBeingEditable())

This indicates that both conditions need to be false for the function to return true:

let fn = (a, b) => {
  if (a) {
    return false;
  }
  if (b) {
    return false;
  }
  return true;
};


console.log(fn(true, true)); // false
console.log(!(true || true)); // false

console.log(fn(false, false)); // true
console.log(!(false || false)); // true

console.log(fn(false, true)); // false
console.log(!(false || true)); // false

console.log(fn(true, false)); // false
console.log(!(true || false)); // false

Answer №3

function checkNoArtistBeingEdited(): boolean {
    return !this.checkFirstNameBeingEdited() && !this.checkLastNameBeingEditable();
}

This code verifies that neither the first name nor the last name is being edited.

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