What is the best way to send a ViewModel property to an ajax post function?

Question

What is the best way to send a ViewModel property to an ajax post function?

 function ResendEmailInvite(internalUserId, familyMemberId) { 
       theinternalUserId = internalUserId;
       theFamilyMemberId = familyMemberId;
      if(confirm('Are you sure you want to resend this family member's invite?')){
         $.ajax({
             type: "POST",
             url:"/Admin/ResendFamilyMemberEmail",
             data: {internalUserId : theinternalUserId, familyMemberId : theFamilyMemberId}, 
             success: function(response){
                alert(response);
             },
             error: function(){
                alert("Error");
            }
        });
        return false;
    }
}

I am utilizing ASP.net MVC 3. This code represents an ajax/javascript method within my view.

In terms of syntax correctness, is there anything wrong with it as far as you can tell?

The value for familyMemberId will be variable, while the userId will remain constant. I aim to pass the userId from my viewModel to this ajax call, what is the best way to achieve this?

javascript ajax asp.net-mvc asp.net-mvc-3

Answer 1

Answer №1

If you're looking to transfer data from the model in your controller to the view, that's what MVC is designed for. According to the MSDN MVC 4 Tutorial:

Controller:

To define your model, you can use the VS menu system and Entity Framework to access the database.

 public class YourController : Controller
{
     private YourDBContext db = new YourDBContext();

     public ActionResult YourAction(int user_id = 0)
    {
        User user = db.Users.find(user_id);
        if(user == null) {
           return HttpNotFound(); // Or unauthorized or whatever
        }
        return View(user);
    }
    //...

View:

@Model IEnumerable<MvcUser.Models.User>

<!-- other stuff -->

 <script type="text/javascript>
 // the rest of your script
        function ResendEmailInvite(internalUserId, familyMemberId) { 
           theinternalUserId = @Model.userId;
           theFamilyMemberId = familyMemberId;
          if(confirm('Are you sure you want to resend this family member's invite?')){
             $.ajax({
                 type: "POST",
                 url:"/Admin/ResendFamilyMemberEmail",
                 data: {internalUserId : theinternalUserId, familyMemberId : theFamilyMemberId}, 
                 success: function(response){
                    alert(response);
                 },
                 error: function(){
                    alert("Error");
                }
            });
            return false;
        }
    }

This method works because, as mentioned, the userId remains static after the page loads. For more dynamic behavior, you'd need another HTML hook for javascript to utilize.

Answer 2

If you're looking to transfer data from the model in your controller to the view, that's what MVC is designed for. According to the MSDN MVC 4 Tutorial:

Controller:

To define your model, you can use the VS menu system and Entity Framework to access the database.

 public class YourController : Controller
{
     private YourDBContext db = new YourDBContext();

     public ActionResult YourAction(int user_id = 0)
    {
        User user = db.Users.find(user_id);
        if(user == null) {
           return HttpNotFound(); // Or unauthorized or whatever
        }
        return View(user);
    }
    //...

View:

@Model IEnumerable<MvcUser.Models.User>

<!-- other stuff -->

 <script type="text/javascript>
 // the rest of your script
        function ResendEmailInvite(internalUserId, familyMemberId) { 
           theinternalUserId = @Model.userId;
           theFamilyMemberId = familyMemberId;
          if(confirm('Are you sure you want to resend this family member's invite?')){
             $.ajax({
                 type: "POST",
                 url:"/Admin/ResendFamilyMemberEmail",
                 data: {internalUserId : theinternalUserId, familyMemberId : theFamilyMemberId}, 
                 success: function(response){
                    alert(response);
                 },
                 error: function(){
                    alert("Error");
                }
            });
            return false;
        }
    }

This method works because, as mentioned, the userId remains static after the page loads. For more dynamic behavior, you'd need another HTML hook for javascript to utilize.

What is the best way to send a ViewModel property to an ajax post function?

Answer №1

Controller:

View:

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