What is the best way to return JSON data as key-value pairs when using the Ajax function $.getJSON()?

Question

What is the best way to return JSON data as key-value pairs when using the Ajax function $.getJSON()?

Here is the ajax code I'm using to fetch JSON data from a Jobs.json file.

 $(document).ready(function(){
        $('#btn2').click( callJobs );
        });

function callJobs()
{


     alert("getting results...");
    $.getJSON('Jobs.json', function(JSON){
        $('#result').empty();

        $.each(JSON.jobs, function(i, JOB){
            $('#result')
            .append(JOB.Job +'<br />')
            .append(JOB.Priority+'<br />')
            .append(JOB.DueDate+'<br />')
            .append(JOB.Iscompleted+'<hr />');
      });
    });
}

Below is the content of the Jobs.json file:

{
"jobs":[
  {
     "Job":"Job1",
     "Priority":"Low",
     "DueDate":"11.03.2013",
     "Iscompleted":"No"
  },
  {
     "Job":"Job2",
     "Priority":"High",
     "DueDate":"11.03.2013",
     "Iscompleted" : "No"
  },
  {
     "Job":"Job3",
     "Priority":"Medium",
     "DueDate":"11.03.2013",
     "Iscompleted":"No"
  }
  ]
  }

I am looking to improve the dynamic functionality of the $.each() function by making it display the JSON string key and value instead of using .append().

javascript ajax json getjson

Answer 1

Answer №1

This function will dynamically iterate through the properties of each job:

$.getJSON('Jobs.json', function(JSON){
    var $container = $('#result').empty();

    $.each(JSON.jobs, function(i, JOB) {
        $.each(JOB, function(key, value) {
            $container.append(key + ': ' + value + '<br />');
        });
        $container.append('<hr />');
    }
});

See it in action

Answer 2

This function will dynamically iterate through the properties of each job:

$.getJSON('Jobs.json', function(JSON){
    var $container = $('#result').empty();

    $.each(JSON.jobs, function(i, JOB) {
        $.each(JOB, function(key, value) {
            $container.append(key + ': ' + value + '<br />');
        });
        $container.append('<hr />');
    }
});

See it in action

Answer 3

Answer №2

Let me break down my approach with some explanatory comments.

$.each(JSON.jobs, function(i, JOB) {
    // Initialize an empty array to store output values
    var values = [];
    // Loop through each property in the current JOB object
    for (var prop in JOB) { 
        // Add each key-value pair to the values array
        values.push(prop + ': ' + JOB[prop]); 
    }
    // Join the array values using '<br />' as a separator; 
    // Append it to #result element and add an '<hr />' afterwards
    $('#result').append(values.join('<br />')).append('<hr />');
});

My main objectives here were to prioritize readability by including an additional array, selecting the #result element only once, and avoiding the need to determine whether to add that last <br /> in each loop iteration. Unlike other solutions, this method does not include an extra <br /> after the final property before the <hr />, which is also consistent with your original solution.

Answer 4

Let me break down my approach with some explanatory comments.

$.each(JSON.jobs, function(i, JOB) {
    // Initialize an empty array to store output values
    var values = [];
    // Loop through each property in the current JOB object
    for (var prop in JOB) { 
        // Add each key-value pair to the values array
        values.push(prop + ': ' + JOB[prop]); 
    }
    // Join the array values using '<br />' as a separator; 
    // Append it to #result element and add an '<hr />' afterwards
    $('#result').append(values.join('<br />')).append('<hr />');
});

My main objectives here were to prioritize readability by including an additional array, selecting the #result element only once, and avoiding the need to determine whether to add that last <br /> in each loop iteration. Unlike other solutions, this method does not include an extra <br /> after the final property before the <hr />, which is also consistent with your original solution.

What is the best way to return JSON data as key-value pairs when using the Ajax function $.getJSON()?

Answer №1

Answer №2

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