What is the best way to retrieve the value of a URL parameter using javascript?

Question

What is the best way to retrieve the value of a URL parameter using javascript?

I need help extracting the value of a specific parameter from a list of URLs.

Here are some examples:

http://example.com/#!/dp/dp.php?g=4346&h=fd34&kl=45fgh&bl=nmkh
http://example.com/#!/dp/dp.php?h=fd34&g=4346&kl=45fgh&bl=nmkh
http://example.com/#!/dp/dp.php?h=fd34&kl=45fgh&g=4346&bl=nmkh
http://example.com/#!/dp/dp.php?h=fd34&kl=45fgh&bl=nmkh&g=4346

I am looking to use JavaScript (regex) to extract the value associated with the g parameter.

Any assistance on how to achieve this would be greatly appreciated!

javascript regex

Answer 1

Answer №1

let regex = url.match(/[?&]g=[^&]*/);
let result = regex[1];

Explained step by step:

[?&]         # starts with a ? or &
g=           # includes g and an equals sign
[^&]*        # followed by any character (except &) repeated 0 or more times

This method is quite simplistic but it should get the job done.

Answer 2

let regex = url.match(/[?&]g=[^&]*/);
let result = regex[1];

Explained step by step:

[?&]         # starts with a ? or &
g=           # includes g and an equals sign
[^&]*        # followed by any character (except &) repeated 0 or more times

This method is quite simplistic but it should get the job done.

Answer 3

Answer №2

let currentURL = window.location.href;
extractParameter("g=", currentURL, "&");

function extractParameter(param, buffer, delimiter)
{
   let startIndex = buffer.indexOf(param);
   if (startIndex == -1)
      return null;
   let newData = buffer.slice(startIndex);
   if(newData.match(delimiter) != null)
      let endIndex = newData.indexOf(delimiter);
   else
      let endIndex = newData.length;
   newData = newData.slice(0, endIndex);
   let equalsPosition = newData.indexOf("=");
   newData = newData.slice(equalsPosition+1);
   return newData;
}

Answer 4

let currentURL = window.location.href;
extractParameter("g=", currentURL, "&");

function extractParameter(param, buffer, delimiter)
{
   let startIndex = buffer.indexOf(param);
   if (startIndex == -1)
      return null;
   let newData = buffer.slice(startIndex);
   if(newData.match(delimiter) != null)
      let endIndex = newData.indexOf(delimiter);
   else
      let endIndex = newData.length;
   newData = newData.slice(0, endIndex);
   let equalsPosition = newData.indexOf("=");
   newData = newData.slice(equalsPosition+1);
   return newData;
}

Answer 5

Answer №3

let values = [];
values = link.match(/[\?\&]g=([^&]*)/);

Extracting the initial value of g is the intended outcome here, not the complete "g=blah" string.

Answer 6

let values = [];
values = link.match(/[\?\&]g=([^&]*)/);

Extracting the initial value of g is the intended outcome here, not the complete "g=blah" string.

Answer 7

Answer №4

Give this a shot:

var currentUrl = window.location.href;
var paramName = 'g';
paramName = paramName.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var match = new RegExp("[\\?&]" + paramName + "=([^&#]*)").exec(currentUrl);
if (match != null)
{
    var paramValue = match[1];
}

Answer 8

Give this a shot:

var currentUrl = window.location.href;
var paramName = 'g';
paramName = paramName.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var match = new RegExp("[\\?&]" + paramName + "=([^&#]*)").exec(currentUrl);
if (match != null)
{
    var paramValue = match[1];
}

Answer 9

Answer №5

let url = 'http://website.com/#!/dp/dp.php?g=4346&h=fd34&kl=45fgh&bl=nmkh';
let regex = /(\&|\?)g=([^&]+)&?/;
console.log(url.match(regex)[2]);

Answer 10

let url = 'http://website.com/#!/dp/dp.php?g=4346&h=fd34&kl=45fgh&bl=nmkh';
let regex = /(\&|\?)g=([^&]+)&?/;
console.log(url.match(regex)[2]);

Answer 11

Answer №6

Utilize this handy function.

function extractValue(param) {

    var match = RegExp('[?&]' + param + '=([^&]*)')
                    .exec(window.location.search);

    return match && decodeURIComponent(match[1].replace(/\+/g, ' '));

}

Use it in the following manner:

var url = "http://domain.com/#!/dp/dp.php?g=4346&h=fd34&kl=45fgh&bl=nmkh";
var value =  extractValue("g");

Note: This code is based on inspiration from James Padolsey's code found at

Answer 12

Utilize this handy function.

function extractValue(param) {

    var match = RegExp('[?&]' + param + '=([^&]*)')
                    .exec(window.location.search);

    return match && decodeURIComponent(match[1].replace(/\+/g, ' '));

}

Use it in the following manner:

var url = "http://domain.com/#!/dp/dp.php?g=4346&h=fd34&kl=45fgh&bl=nmkh";
var value =  extractValue("g");

Note: This code is based on inspiration from James Padolsey's code found at

What is the best way to retrieve the value of a URL parameter using javascript?

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

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