What is the best way to merge several filters into one filter function in order to retrieve data for a specific month?

Question

What is the best way to merge several filters into one filter function in order to retrieve data for a specific month?

A smarter approach to improve efficiency and reduce time complexity (n^3) while retrieving all variables.

getrewarddata represents an object
d1, d2, d3... are individual variables

//Object contains various rewards for different months
const getrewarddata = [{
        month: 6,
        year: 2021,
        reward: 6,
    },
    {
        month: 1,
        year: 2021,
        reward: 6,
    },
    {
        month: 3,
        year: 2021,
        reward: 6,
    },
];

//Split the array based on specific month variable
let d3 = getrewarddata.filter((data) => data.month === 3);

let d2 = getrewarddata.filter((data) => data.month === 2);

let d1 = getrewarddata.filter((data) => data.month === 1);

console.log(d2);
console.log(d3);

javascript arrays time-complexity

Answer 1

Answer №1

A possible solution is to use a grouping method. You can refer to this approach which seems to work well:

//Object has multiple rewards and different month
const getrewarddata = [{
        month: 6,
        year: 2021,
        reward: 6,
    },
    {
        month: 1,
        year: 2021,
        reward: 6,
    },
    {
        month: 3,
        year: 2021,
        reward: 6,
    },
];

var groupBy = function(xs, key) {
  return xs.reduce(function(rv, x) {
    (rv[x[key]] = rv[x[key]] || []).push(x);
    return rv;
  }, {});
};


var groupedByMonth = groupBy(getrewarddata, "month");

console.log(groupedByMonth);

Answer 2

A possible solution is to use a grouping method. You can refer to this approach which seems to work well:

//Object has multiple rewards and different month
const getrewarddata = [{
        month: 6,
        year: 2021,
        reward: 6,
    },
    {
        month: 1,
        year: 2021,
        reward: 6,
    },
    {
        month: 3,
        year: 2021,
        reward: 6,
    },
];

var groupBy = function(xs, key) {
  return xs.reduce(function(rv, x) {
    (rv[x[key]] = rv[x[key]] || []).push(x);
    return rv;
  }, {});
};


var groupedByMonth = groupBy(getrewarddata, "month");

console.log(groupedByMonth);

Answer 3

Answer №2

To simplify this process, consider creating a function that acts as a helper or wrapper to avoid repeating the same code.

const dataFilter = (month) => getrewarddata.filter((data) => data.month === month);

You can then utilize this helper function like so:

let month3Data = dataFilter(3);
let month2Data = dataFilter(2);
let month1Data = dataFilter(1);

Answer 4

To simplify this process, consider creating a function that acts as a helper or wrapper to avoid repeating the same code.

const dataFilter = (month) => getrewarddata.filter((data) => data.month === month);

You can then utilize this helper function like so:

let month3Data = dataFilter(3);
let month2Data = dataFilter(2);
let month1Data = dataFilter(1);

Answer 5

Answer №3

Your code snippet appears to be functioning correctly, but it's not entirely clear what your end goal is. One suggestion would be to create a reusable function that can be called for each variable, which could help reduce the amount of repetitive code you currently have.

const rewardData = [{
        month: 6,
        year: 2021,
        reward: 6,
    },
    {
        month: 1,
        year: 2021,
        reward: 6,
    },
    {
        month: 3,
        year: 2021,
        reward: 6,
    },
];

function filterByMonth(arr, n){
    return arr.filter((data) => data.month === n)
}

let januaryRewards = filterByMonth(rewardData, 1)
let marchRewards = filterByMonth(rewardData, 3)
console.log(januaryRewards)
console.log(marchRewards)

Answer 6

Your code snippet appears to be functioning correctly, but it's not entirely clear what your end goal is. One suggestion would be to create a reusable function that can be called for each variable, which could help reduce the amount of repetitive code you currently have.

const rewardData = [{
        month: 6,
        year: 2021,
        reward: 6,
    },
    {
        month: 1,
        year: 2021,
        reward: 6,
    },
    {
        month: 3,
        year: 2021,
        reward: 6,
    },
];

function filterByMonth(arr, n){
    return arr.filter((data) => data.month === n)
}

let januaryRewards = filterByMonth(rewardData, 1)
let marchRewards = filterByMonth(rewardData, 3)
console.log(januaryRewards)
console.log(marchRewards)

Answer 7

Answer №4

Here is a different approach that involves iterating over the array only once.

let organizedData = getrewarddata.reduce((accumulator, entry) => {
        if (accumulator[entry.month] == undefined) { 
            accumulator[entry.month] = [entry];
        } else {
            accumulator[entry.month].push(entry);
        }
        return accumulator;
    }, {})

With this method, you will obtain an object structured like this:

{
    "1": [
        {
            "month": 1,
            "year": 2021,
            "reward": 6
        }
    ],
    "3": [
        {
            "month": 3,
            "year": 2021,
            "reward": 6
        }
    ],
    "6": [
        {
            "month": 6,
            "year": 2021,
            "reward": 6
        }
    ]
}

You can now access this data in a similar way as a regular object

organizedData[1]
=> [{
        "month": 1,
        "year": 2021,
        "reward": 6
    }]

Answer 8

Here is a different approach that involves iterating over the array only once.

let organizedData = getrewarddata.reduce((accumulator, entry) => {
        if (accumulator[entry.month] == undefined) { 
            accumulator[entry.month] = [entry];
        } else {
            accumulator[entry.month].push(entry);
        }
        return accumulator;
    }, {})

With this method, you will obtain an object structured like this:

{
    "1": [
        {
            "month": 1,
            "year": 2021,
            "reward": 6
        }
    ],
    "3": [
        {
            "month": 3,
            "year": 2021,
            "reward": 6
        }
    ],
    "6": [
        {
            "month": 6,
            "year": 2021,
            "reward": 6
        }
    ]
}

You can now access this data in a similar way as a regular object

organizedData[1]
=> [{
        "month": 1,
        "year": 2021,
        "reward": 6
    }]

What is the best way to merge several filters into one filter function in order to retrieve data for a specific month?

Answer №1

Answer №2

Answer №3

Answer №4

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