What is the best way to locate the most negative integer within an array?

let test12 = [-1, -2, -3];

I'm having trouble with this one. I've been able to solve it for positive integers using the code below, but I'm not sure how to modify it for negative numbers.

let test = [1 , 2, 3];

var largest= 0;

for (i=0; i<=test.length;i++){
    if (test[i]>largest) {
        largest=test[i];
    }
}
console.log(largest);

Answer №1

Finding the largest negative integer in an array

When looking for the largest negative integer in an array, there are a few interpretations to consider:

  1. The negative integer that is furthest from 0
  2. The negative integer that is closest to 0
  3. The overall largest number in the array (this can be tricky if the array consists solely of negative integers)

It's important to note that the 'smallest' refers to the negative integer that is farthest from zero. Here's a code snippet demonstrating all three interpretations:

const ints = [-3, -2, -1, 0, 1, 2]

const negativeInts = ints.filter(i => i < 0)

const smallestNegative = Math.min(...negativeInts)
const largestNegative = Math.max(...negativeInts)
const largestOverall = Math.max(...ints)
console.log({smallestNegative, largestNegative, largestOverall}) // Output: -3, -1, 2

I hope this explanation helps you understand how to find the largest negative integer in an array. Cheers!

Answer №2

To start, set largest to negative infinity instead of 0. Remember to loop through the entire input array's length, not from 0 to largest:

let test12 = [-1, -2, -3];
var largest = -Infinity;
for (i = 0; i < test12.length; i++) {
  if (test12[i] > largest) {
    var largest = test12[i];
  }
}
console.log(largest);

Alternatively, you can use spread syntax with Math.max:

let test12 = [-1, -2, -3];
console.log(
  Math.max(...test12)
);

Answer №3

If you ever find yourself in need of a programming solution, such as making an edit to your program even when dealing with an array full of negative numbers, then consider the following approach:

let test = [-10, -1, -2, -3];
// Start by assigning the first element in the test array to the variable 'largest'.
// While the largest integer might not be greater than zero,
// it will definitely be larger than any other element in the array.
var largest = test[0];

for (i = 0; i <= test.length; i++) {
    if (test[i] > largest) {
        largest = test[i];
    }
}
console.log(largest);

Answer №4

The most substantial negative number would be -244, so by sorting the array, you can easily retrieve the first index with that value.

const numbers = [-1, -2, -244, -7];
    [largest] = numbers.slice().sort((a, b) => a - b);
console.log(largest);

Answer №5

Give this a shot!

let numbers = [23, 56, -7, 45, 0, -12, 34];
numbers.sort(function(a, b) {
  return a - b;
});
console.log(numbers[0]);

Answer №6

private static void executeCode(String[] arguments) {

    int[] numbers = {10, 20, -5, 15, 30, 25};
    System.out.println(findMaxAbs(numbers));
}
public static int findMaxAbs(int[] numbers) {

  // public int getLargestNegative(int[] array) {
        int maximum = 0;
        for (int index = 0; index < numbers.length; index++) {
            if (numbers[index] < 0) {
                if (maximum == 0 || numbers[index] > maximum) {
                    maximum = numbers[index];
                }
            }
        }
        return maximum;
    }
}

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