What is the best way to indicate that two different array positions are equal to at least one of the specified values within a conditional statement?

Can someone help me with expressing in JavaScript that if both array1[i] and array2[j] equal either "0", "O" or "Q", then array1[i] should be equal to array2[j? I've tried different approaches but it's not working. Thank you.

if ((array1[i] == "0" || array1[i] == "O" || array1[i] == "Q") && (array2[j] == "0" || array2[j] == "O" || array2[j] == "Q")){
          array1[i] = array2[j];
}

or

if ((array1[i] == "0" || array1[i] == "O" || array1[i] == "Q") && (array2[j] == "0" || array2[j] == "O" || array2[j] == "Q")){
              array1[i] = array2[j];
}

Answer №1

To validate whether the arrays contain certain values, you can create a separate array and use the includes method.

const checkArray = ['A', 'B', 'C'];
if (checkArray.includes(array1[i]) && checkArray.includes(array2[j])) {
  console.log("Both arrays have A, B, or C");
}

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