What is the best way to include keys in my JSON data, rather than just values?

Question

What is the best way to include keys in my JSON data, rather than just values?

I've encountered an issue with the PrimeVue datatable I created, as it is only showing empty rows.

After investigating, I believe the problem lies in my JSON data structure, where the fields do not have keys. What modifications should be made to standardize this JSON so that my data can be properly displayed? Thank you in advance for your assistance.

An example of the current JSON structure:

[
   [
    32,
    "DE BELLOUET Jag",
    "1.3.13.3.",
    "Cid polseruti sau"
   ],
   [
    15,
    "NOURAUD Benjamin",
    "1.3.13.3.",
    "Cid polseruti sau"
   ]
]

An example of the desired JSON structure:

[
   {
    "id":32,
    "fullName":"DE BELLOUET Jag",
    "acs":"1.3.13.3.",
    "nom_service":"Cid polseruti sau"
   },
   {
    "id":15,
    "fullName":"NOURAUD Benjamin",
    "acs":"1.3.13.3.",
    "nom_service":"Cid polseruti sau"
   }
]

Main program file: gererPersonnes.vue

... ...

javascript java vue.js rest primevue

Answer 1

Answer №1

The data you're looking for is not in json format. Here is the information you actually need :

[
   {
    "id":32,
    "fullName":"DE BELLOUET Jag",
    "acs":"1.3.13.3.",
    "nom_service":"Cid polseruti sau"
   },
   {
    "id":15,
    "fullName":"NOURAUD Benjamin",
    "acs":"1.3.13.3.",
    "nom_service":"Cid polseruti sau"
   }
]

It's important to note the { and } symbols that indicate an Object or a map of properties.

To handle this data effectively, consider creating a POJO (Plain Old Java Object) like this:

public class Agent {
    private Integer id;
    private String fullName;
    private String acs;
    private String nomService;

    // include getters and setters here

}

If you need to return multiple Agents, consider using a List<Agent> in your method. If necessary, explore the Jackson library for serializing a List<Agent> into json format.

Answer 2

The data you're looking for is not in json format. Here is the information you actually need :

[
   {
    "id":32,
    "fullName":"DE BELLOUET Jag",
    "acs":"1.3.13.3.",
    "nom_service":"Cid polseruti sau"
   },
   {
    "id":15,
    "fullName":"NOURAUD Benjamin",
    "acs":"1.3.13.3.",
    "nom_service":"Cid polseruti sau"
   }
]

It's important to note the { and } symbols that indicate an Object or a map of properties.

To handle this data effectively, consider creating a POJO (Plain Old Java Object) like this:

public class Agent {
    private Integer id;
    private String fullName;
    private String acs;
    private String nomService;

    // include getters and setters here

}

If you need to return multiple Agents, consider using a List<Agent> in your method. If necessary, explore the Jackson library for serializing a List<Agent> into json format.

Answer 3

Answer №2

To tackle the issue at hand, a new class named AgentServ must be created as the initial step in the solution.

Unfortunately, hibernate presented a hiccup when processing my request, necessitating the use of a list of Object[] to store the results.

Each set of results needed to be carefully cast and incorporated into an agent object before eventually being added to the list.

Finally, the datatable successfully displays the desired outcome.

Here is the finalized code snippet:

public List<AgentServ> listAgentService() {
    String buf = null;
    buf = "SELECT a.id AS id,(btrim(a.nom) || ' ' || btrim(a.prenom)) AS fullName, s.acs AS acs, s.libelle AS nom_service ";
    buf += "FROM Agent a INNER JOIN Service s ON a.service = s ";
    buf += "WHERE ((a.actif = true) OR ((a.actif = false) AND (a.dateSuppression >= CURRENT_DATE)))";

    List<Object[]> query = em.createQuery(buf.toString(), Object[].class).getResultList();
    List<AgentServ> agents = new ArrayList<AgentServ>();
    
    for(Object[] row : query) {
        AgentServ agent = new AgentServ();
        agent.setId((long) row[0]);
        agent.setFullName((String) row[1]);
        agent.setAcs((String) row[2]);
        agent.setNom_service((String) row[3]);
        
        agents.add(agent);
    }
    
    return agents;      
}

Answer 4

To tackle the issue at hand, a new class named AgentServ must be created as the initial step in the solution.

Unfortunately, hibernate presented a hiccup when processing my request, necessitating the use of a list of Object[] to store the results.

Each set of results needed to be carefully cast and incorporated into an agent object before eventually being added to the list.

Finally, the datatable successfully displays the desired outcome.

Here is the finalized code snippet:

public List<AgentServ> listAgentService() {
    String buf = null;
    buf = "SELECT a.id AS id,(btrim(a.nom) || ' ' || btrim(a.prenom)) AS fullName, s.acs AS acs, s.libelle AS nom_service ";
    buf += "FROM Agent a INNER JOIN Service s ON a.service = s ";
    buf += "WHERE ((a.actif = true) OR ((a.actif = false) AND (a.dateSuppression >= CURRENT_DATE)))";

    List<Object[]> query = em.createQuery(buf.toString(), Object[].class).getResultList();
    List<AgentServ> agents = new ArrayList<AgentServ>();
    
    for(Object[] row : query) {
        AgentServ agent = new AgentServ();
        agent.setId((long) row[0]);
        agent.setFullName((String) row[1]);
        agent.setAcs((String) row[2]);
        agent.setNom_service((String) row[3]);
        
        agents.add(agent);
    }
    
    return agents;      
}

What is the best way to include keys in my JSON data, rather than just values?

Answer №1

Answer №2

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