What is the best way to include a file object within a JavaScript object?

Question

What is the best way to include a file object within a JavaScript object?

What is the method for adding an object to an existing javascript object? Below is an example of an existing javascript object

   var dataObj = {
       TITLE : adtitle,
       DESC : addesc,
       PRICE : price,
       DISCOUNT : discount,
       CATID : maincatid,
       STATUS : adstatus,
       QUANTITY : quantity  
   };

I have a file object that I would like to add to the above object.

File { name: "paper.jpg", lastModified: 1445433597723, lastModifiedDate: Date 2015-10-21T13:19:57.723Z, size: 54900, type: "image/jpeg" }

This file object is obtained from a file upload input field

var image1 = $('#Image1').prop("files")[0];
var image2 = $('#Image2').prop("files")[0];

Additionally, a $.post request needs to be executed

   $.post("<?php echo Yii::app()->createUrl('/post'); ?>", { jsonData: postdata}, function(response){
            console.log(response);
        });

All these scripts are triggered upon clicking a button

   $('#postit').click(function(e){
          //all the mentioned scripts
   });

javascript json

Answer 1

Answer №1

If you want to include it in an existing object, all you have to do is create a new property in your dataObj:

var dataObj = {
    ...
};
// additional steps
dataObj.FILE = $('#Image1').prop("files")[0];

Alternatively, if possible, add it when defining the dataObj initially:

var dataObj = {
   TITLE : adtitle,
   DESC : addesc,
   PRICE : price,
   DISCOUNT : discount,
   CATID : maincatid,
   STATUS : adstatus,
   QUANTITY : quantity,
   FILE : $('#Image1').prop("files")[0]
};

For multiple File objects, store them as an array within your dataObj:

dataObj.FILES = $('#Image1').prop("files");

In cases where you are dealing with one file at a time and need to push them individually into an array on your dataObj:

var dataObj = {
   TITLE : adtitle,
   DESC : addesc,
   PRICE : price,
   DISCOUNT : discount,
   CATID : maincatid,
   STATUS : adstatus,
   QUANTITY : quantity,
   FILES : []
};

// Fill the array
$('#Image1').prop("files").forEach(function(file) {
    dataObj.FILES.push(file);
});

Answer 2

If you want to include it in an existing object, all you have to do is create a new property in your dataObj:

var dataObj = {
    ...
};
// additional steps
dataObj.FILE = $('#Image1').prop("files")[0];

Alternatively, if possible, add it when defining the dataObj initially:

var dataObj = {
   TITLE : adtitle,
   DESC : addesc,
   PRICE : price,
   DISCOUNT : discount,
   CATID : maincatid,
   STATUS : adstatus,
   QUANTITY : quantity,
   FILE : $('#Image1').prop("files")[0]
};

For multiple File objects, store them as an array within your dataObj:

dataObj.FILES = $('#Image1').prop("files");

In cases where you are dealing with one file at a time and need to push them individually into an array on your dataObj:

var dataObj = {
   TITLE : adtitle,
   DESC : addesc,
   PRICE : price,
   DISCOUNT : discount,
   CATID : maincatid,
   STATUS : adstatus,
   QUANTITY : quantity,
   FILES : []
};

// Fill the array
$('#Image1').prop("files").forEach(function(file) {
    dataObj.FILES.push(file);
});

Answer 3

Answer №2

I'm not completely certain if that fully addresses your inquiry, but in simplest terms the answer is as follows:

dataObj.FILE = image1;

Answer 4

I'm not completely certain if that fully addresses your inquiry, but in simplest terms the answer is as follows:

dataObj.FILE = image1;

What is the best way to include a file object within a JavaScript object?

Answer №1

Answer №2

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