What is the best way to implement a Fibonacci sequence using a for...of loop?

Question

What is the best way to implement a Fibonacci sequence using a for...of loop?

**Can someone show me how to generate Fibonacci numbers using the for...of loop in JavaScript?**

I've tested out the following code and it's giving me the desired output:


function createFibonacci(number) {
    var i;
    var fib = []; // Initial array set up

    fib[0] = 0;
    fib[1] = 1;
    for (i = 2; i <= number; i++) {
        // Logic to find next Fibonacci number
        fib[i] = fib[i - 2] + fib[i - 1];
        console.log(fib[i]);
    }
}

createFibonacci(8);

Although this works fine, I'm curious if there's a way to achieve the same result using the for..of loop. Is there any method available for this?

javascript

Answer 1

Answer №1

Here is a suggestion for generating Fibonacci numbers using a generator in JavaScript:

function generateFibonacciNumbers(num) {
  // fibonacci generator
  const gen = (function *(i) {
    let a = 1, b = 1, c;
    if (i--) yield a;
    if (i--) yield b;
    while (i--) {
      yield c = a + b;
      [a, b] = [b, c];
    }
  });

  for (let fib of gen(num)) {
    console.log(fib);
  }
}

generateFibonacciNumbers(8);

As noted by @T.J. Crowder, the sequence is actually generated by the generator and consumed using the for...of loop.

Answer 2

Here is a suggestion for generating Fibonacci numbers using a generator in JavaScript:

function generateFibonacciNumbers(num) {
  // fibonacci generator
  const gen = (function *(i) {
    let a = 1, b = 1, c;
    if (i--) yield a;
    if (i--) yield b;
    while (i--) {
      yield c = a + b;
      [a, b] = [b, c];
    }
  });

  for (let fib of gen(num)) {
    console.log(fib);
  }
}

generateFibonacciNumbers(8);

As noted by @T.J. Crowder, the sequence is actually generated by the generator and consumed using the for...of loop.

Answer 3

Answer №2

Consider utilizing a generator function.

function* generateFibonacci(number, a = 0, b = 1) {
    if (a === 0)
        if (number--) yield 1;
        else return;
    if (!number--) return
    yield a + b;
    yield* generateFibonacci(number, b, a + b);
}

console.log(...generateFibonacci(0));
console.log(...generateFibonacci(1));
console.log(...generateFibonacci(2));
console.log(...generateFibonacci(3));
console.log(...generateFibonacci(4));
console.log(...generateFibonacci(5));
console.log(...generateFibonacci(6));
console.log(...generateFibonacci(7));
console.log(...generateFibonacci(8));

.as-console-wrapper { max-height: 100% !important; top: 0; }

An alternative method inspired by assistance from Rup.

function* generateFibonacci(number, index = 1) {
    generateFibonacci.values = generateFibonacci.values || [0, 1];
    for (; index < generateFibonacci.values.length && index < number + 1; ++index)
        yield generateFibonacci.values[index];
    if (index >= number + 1) return;
    yield generateFibonacci.values[index] = generateFibonacci.values[index - 2] + generateFibonacci.values[index - 1];
    yield* generateFibonacci(number, index + 1);
}

console.log(...generateFibonacci(0));
console.log(...generateFibonacci(1));
console.log(...generateFibonacci(2));
console.log(...generateFibonacci(3));
console.log(...generateFibonacci(4));
console.log(...generateFibonacci(5));
console.log(...generateFibonacci(6));
console.log(...generateFibonacci(7));
console.log(...generateFibonacci(8));

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 4

Consider utilizing a generator function.

function* generateFibonacci(number, a = 0, b = 1) {
    if (a === 0)
        if (number--) yield 1;
        else return;
    if (!number--) return
    yield a + b;
    yield* generateFibonacci(number, b, a + b);
}

console.log(...generateFibonacci(0));
console.log(...generateFibonacci(1));
console.log(...generateFibonacci(2));
console.log(...generateFibonacci(3));
console.log(...generateFibonacci(4));
console.log(...generateFibonacci(5));
console.log(...generateFibonacci(6));
console.log(...generateFibonacci(7));
console.log(...generateFibonacci(8));

.as-console-wrapper { max-height: 100% !important; top: 0; }

An alternative method inspired by assistance from Rup.

function* generateFibonacci(number, index = 1) {
    generateFibonacci.values = generateFibonacci.values || [0, 1];
    for (; index < generateFibonacci.values.length && index < number + 1; ++index)
        yield generateFibonacci.values[index];
    if (index >= number + 1) return;
    yield generateFibonacci.values[index] = generateFibonacci.values[index - 2] + generateFibonacci.values[index - 1];
    yield* generateFibonacci(number, index + 1);
}

console.log(...generateFibonacci(0));
console.log(...generateFibonacci(1));
console.log(...generateFibonacci(2));
console.log(...generateFibonacci(3));
console.log(...generateFibonacci(4));
console.log(...generateFibonacci(5));
console.log(...generateFibonacci(6));
console.log(...generateFibonacci(7));
console.log(...generateFibonacci(8));

.as-console-wrapper { max-height: 100% !important; top: 0; }

What is the best way to implement a Fibonacci sequence using a for...of loop?

Answer №1

Answer №2

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