What is the best way to find unique characters along with their frequency in JavaScript?

Question

What is the best way to find unique characters along with their frequency in JavaScript?

Can you help me adjust this code in order to receive the desired output: "T-1 r-1 a-1 e-1 "

(other characters are repeating. So no need to print the others)

function checkUniqueCharacters() {

    var uniqueChars = [];
    var count = 0;
    var fullName = "Trammell";
    var stringLength = fullName.length;

    for (var i = 0; i < stringLength; i++) {
        for (var j = 0; j < stringLength; j++) {
            var char1 = fullName.charAt(i);
            var char2 = fullName.charAt(j);

            if (char1 != char2) {
                uniqueChars[count] = char1;
                count++;
            }
        }

        count = 0;
    }
}

javascript arrays loops

Answer 1

Answer №1

The solution to your problem involves counting the occurrences of each character in a given string and outputting those that occur only once.

var uniqueChars = [];
var testString = "Hello";

for (var i = 0; i < testString.length; i++)
{
    var character = testString[i];
    if (!(character in uniqueChars))
    {
        uniqueChars[character] = 1;
    }
    else
    {
        uniqueChars[character] = uniqueChars[character] + 1;
    }
}

var result = "";
for (var character in uniqueChars)
{
    if (uniqueChars[character] == 1)
    {
        result += character + "-" + uniqueChars[character] + " ";
    }
}

alert(result);

When executed, this code will display the following output:

H-1 e-1

Answer 2

The solution to your problem involves counting the occurrences of each character in a given string and outputting those that occur only once.

var uniqueChars = [];
var testString = "Hello";

for (var i = 0; i < testString.length; i++)
{
    var character = testString[i];
    if (!(character in uniqueChars))
    {
        uniqueChars[character] = 1;
    }
    else
    {
        uniqueChars[character] = uniqueChars[character] + 1;
    }
}

var result = "";
for (var character in uniqueChars)
{
    if (uniqueChars[character] == 1)
    {
        result += character + "-" + uniqueChars[character] + " ";
    }
}

alert(result);

When executed, this code will display the following output:

H-1 e-1

Answer 3

Answer №2

This approach gets the job done, but there may be more efficient methods available!

let input = "sample input";
let charArray = [];
let output = "";

for (let i = 0; i < input.length; i++){
    let charObj = {"Char": input.charAt(i), "Passed": false};   
    charArray.push(charObj);
}

for (let i = 0; i < charArray.length; i++){
    if (!charArray[i].Passed && charArray[i].Char !== " "){
        let count = countOccurrences(input, charArray[i].Char);
        if (count === 1){
            output += charArray[i].Char + "-" + count + " ";
        }
        charArray[i].Passed = true;
    }
}

console.log(output);

function countOccurrences(input, char){
    let count = 0;
    for (let i = 0; i < input.length; i++){
        if (input.charAt(i) === char){
            count++;
        }
    }
    return count;
}

Answer 4

This approach gets the job done, but there may be more efficient methods available!

let input = "sample input";
let charArray = [];
let output = "";

for (let i = 0; i < input.length; i++){
    let charObj = {"Char": input.charAt(i), "Passed": false};   
    charArray.push(charObj);
}

for (let i = 0; i < charArray.length; i++){
    if (!charArray[i].Passed && charArray[i].Char !== " "){
        let count = countOccurrences(input, charArray[i].Char);
        if (count === 1){
            output += charArray[i].Char + "-" + count + " ";
        }
        charArray[i].Passed = true;
    }
}

console.log(output);

function countOccurrences(input, char){
    let count = 0;
    for (let i = 0; i < input.length; i++){
        if (input.charAt(i) === char){
            count++;
        }
    }
    return count;
}

What is the best way to find unique characters along with their frequency in JavaScript?

Answer №1

Answer №2

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