What is the best way to extract percentage values from a string using a regular expression?

Question

What is the best way to extract percentage values from a string using a regular expression?

Is there a way to extract percentage values from a string without including the percent sign?

I am trying to retrieve the numbers from the string, excluding the % symbol. Currently, my code works but includes the percent sign in the output:

"asfd %1.3344 %1.2323 % asdf %".match(/%[0-9.]*/g)

Result:

["%1.3344", "%1.2323", "%", "%" ]

But I want the result to be [ 1.3344, 1.2323]

I attempted using a regex look ahead, but it didn't work as expected and returned an array of empty strings:

"asfd %1.3344 %1.2323 % asdf %".match(/(?=%)[0-9.]*/g)

result: ["", "", "", "" ]

javascript regex mongodb

Answer 1

Answer №1

"Discovering the magic within strings - extracting numerical values using JavaScript regex".match(/%[0-9.]+/g).map( function (item) { return item.substr(1); })

Answer 2

"Discovering the magic within strings - extracting numerical values using JavaScript regex".match(/%[0-9.]+/g).map( function (item) { return item.substr(1); })

Answer 3

Answer №2

To solve this issue, the common approach is to group the desired content and utilize exec within a loop:

var re = /%(\d+(?:\.\d*)?)/g;
var percentages = [];
var m;

while(m = re.exec(str)) {
    percentages.push(+m[1]);
}

It's worth noting the stricter regular expression used: it looks for at least one digit, followed by an optional decimal point and any number of additional digits.

Answer 4

To solve this issue, the common approach is to group the desired content and utilize exec within a loop:

var re = /%(\d+(?:\.\d*)?)/g;
var percentages = [];
var m;

while(m = re.exec(str)) {
    percentages.push(+m[1]);
}

It's worth noting the stricter regular expression used: it looks for at least one digit, followed by an optional decimal point and any number of additional digits.

Answer 5

Answer №3

I think this approach will also solve the problem.

Sample JavaScript code snippet:

var str = "This is a sample string with %1.3344 some numbers %1.2323 % included",
    arr = [];

str.replace(/%(\d+(?:\.\d*)?)/g, function (match, number) {
    arr.push(number);
});

console.log(arr);

Check out this jsFiddle for demonstration

Answer 6

I think this approach will also solve the problem.

Sample JavaScript code snippet:

var str = "This is a sample string with %1.3344 some numbers %1.2323 % included",
    arr = [];

str.replace(/%(\d+(?:\.\d*)?)/g, function (match, number) {
    arr.push(number);
});

console.log(arr);

Check out this jsFiddle for demonstration

Answer 7

Answer №4

After doing some research, I came across a possible solution:

var str="asfd %1.3344 %1.2323 % asdf %";
var patt=/%([0-9\.]+)/g;
var result;
while(null != (result = patt.exec(str))){
    document.write(result[1] + '<br />');
}

Answer 8

After doing some research, I came across a possible solution:

var str="asfd %1.3344 %1.2323 % asdf %";
var patt=/%([0-9\.]+)/g;
var result;
while(null != (result = patt.exec(str))){
    document.write(result[1] + '<br />');
}

Answer 9

Answer №5

This particular regular expression seems to be quite effective in this scenario without the need for a loop.

var str = "asfd %1.3344 %1.2323 % asdf %", resultsArray;
resultsArray = str.replace(/(^[^%]+)|[^\d .]|( (?!%\d))/g,'').split(' ');

By using the Split String method, you can obtain an array of values.

If there are other types of patterns that may appear in your input (such as consecutive dots like "asfd %1.. %1.23" or any other variations), please inform me so we can adjust the regular expression accordingly.

Answer 10

This particular regular expression seems to be quite effective in this scenario without the need for a loop.

var str = "asfd %1.3344 %1.2323 % asdf %", resultsArray;
resultsArray = str.replace(/(^[^%]+)|[^\d .]|( (?!%\d))/g,'').split(' ');

By using the Split String method, you can obtain an array of values.

If there are other types of patterns that may appear in your input (such as consecutive dots like "asfd %1.. %1.23" or any other variations), please inform me so we can adjust the regular expression accordingly.

What is the best way to extract percentage values from a string using a regular expression?

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

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