What is the best way to confirm if the elements in an array are in consecutive order?

Is there a way to determine if an array's members are consecutive?

For instance, the array [1,3,4,5,6] is not considered consecutive because it is missing the number 2 in the sequence. Which JavaScript array methods can be used to check for this type of pattern?

I've experimented with JavaScript array methods like ".map", ".every", and ".some", but haven't had any success.

   let values = [1,3,4,5,6];

   let result1 = values.map(x => x > 5);
   console.log('value of result1 : ', result1);
   Result: "value of result1 : ", [false, false, false, false, true]

   let result2 = values.some(x => x > 5);
   console.log('value of result2 : ', result2);
   Result: "value of result2 : ", true
   
   let result5 = values.every(x => x > 4);
   console.log('value of result5 : ', result5);
   Result: "value of result5 : ", false

Thank you...

Answer №1

To implement the every function, use the following code snippet:

values.every((num, i) => i === values.length - 1 || num === values[i + 1] -1 )

let values = [1,3,4,5,6];
console.log(values.every((num, i) => i === values.length - 1 || num === values[i + 1] -1 ));

Answer №2

This concept is designed to be quick and easily comprehensible:

function checkConsecutive(array) {
  for (let i = 1; i < array.length; i++) {
    if (array[i] !== array[i - 1] + 1) {
      return false;
    }
  }
  return true;
}

Iterating from index 1, we compare each element with its predecessor.

Answer №3

Using a straightforward loop is another effective strategy.

function consecutiveNumbers(arr) {
  let prev = arr[0];
  for (var i = 1; i < arr.length - 1; i++) {
    if (prev + 1 !== arr[i]) return false;
    prev = arr[i];
  }
  return true;
}

let values = [1, 3, 4, 5, 6];
console.log(consecutiveNumbers(values));

Answer №4

Use the <code>slice method, followed by some to easily compare adjacent values in an array:

var array = [1, 2, 4, 5, 7];
var result = array.slice(1).some((value, index) => value != array[index] + 1);
console.log(result);

Answer №5

For a bit of amusement, here's a solution using reduce. However, it's not recommended for real code as the next person who sees it might be tempted to do something drastic.

const increasing = arr.reduce(([p, v], c) => ([c, (c >= p) && v]), [arr[0], true])[1]

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