What is the best way to compare two arrays of different lengths in JavaScript?

Question

What is the best way to compare two arrays of different lengths in JavaScript?

Consider two arrays, Array1 and Array2, that need to be compared based on the following three rules:

Rule 1:

Array1=[en,fr,eg];
Array2=[{lang:en},{lang:eg}]

The comparison result will be:

Result=[{lang:en},{lang:fr,Maybe:i_can_add_other_Attribute},{lang:eg}]

Rule 2:

If Array1=[en,fr,eg] and Array2=[{lang:en},{lang:fr}], then the result should be Result[{lang:en},{lang:fr}]

Rule 3:

Array2 must be arranged in the sequence of Array1. For example:

Array1=[en,fr,eg]
Array2=[{lang:fr},{lang:en},{lang:eg}]

In this case, the result should become:

 Result=[{lang:en},{lang:fr},{lang:eg}]

javascript arrays arraylist data-structures

Answer 1

Answer №1

If you're more interested in the contents of Array rather than Array2, and wish to generate a new array directly from the elements in Array1, you can achieve this easily using Array.prototype.map:

const Array1 = [ 'en', 'fr', 'eg' ];
let Array2 = [ {lang:'eg'}, {lang:'fr'}, 'mashed potatoes' ];

Array2 = Array1.map( lang => ({ lang }) );

console.log( Array2 );

Answer 2

If you're more interested in the contents of Array rather than Array2, and wish to generate a new array directly from the elements in Array1, you can achieve this easily using Array.prototype.map:

const Array1 = [ 'en', 'fr', 'eg' ];
let Array2 = [ {lang:'eg'}, {lang:'fr'}, 'mashed potatoes' ];

Array2 = Array1.map( lang => ({ lang }) );

console.log( Array2 );

Answer 3

Answer №2

If you'd like to incorporate values from Array2 whenever possible, you can use the following approach:

const List1 = [ 'apple', 'banana', 'cherry' ];
const List2 = [ { fruit: 'apple' }, { fruit: 'cherry' } ];

const combinedList = List1.map(item =>
  List2.find(obj => obj.fruit === item) || { fruit: item }
);

Answer 4

If you'd like to incorporate values from Array2 whenever possible, you can use the following approach:

const List1 = [ 'apple', 'banana', 'cherry' ];
const List2 = [ { fruit: 'apple' }, { fruit: 'cherry' } ];

const combinedList = List1.map(item =>
  List2.find(obj => obj.fruit === item) || { fruit: item }
);

Answer 5

Answer №3

Based on my understanding, you currently have an array containing all available languages and another array of objects providing additional properties for each language. To optimize this process and improve data representation, I suggest saving the second array as an object:

let langWithProps = {
  en: {},
  fr: {}
  ...
}

You can then follow this approach:

let langWithProps = {
  en: {},
  fr: {}
}

const langs = [ 'en', 'fr', 'eg' ];

langs.forEach(function(value) {
    if (!langWithProps[value]) {
        langWithProps[value] = {Maybe: "you_can_add_other_Attribute"};
    }
});

console.log(langWithProps);

Answer 6

Based on my understanding, you currently have an array containing all available languages and another array of objects providing additional properties for each language. To optimize this process and improve data representation, I suggest saving the second array as an object:

let langWithProps = {
  en: {},
  fr: {}
  ...
}

You can then follow this approach:

let langWithProps = {
  en: {},
  fr: {}
}

const langs = [ 'en', 'fr', 'eg' ];

langs.forEach(function(value) {
    if (!langWithProps[value]) {
        langWithProps[value] = {Maybe: "you_can_add_other_Attribute"};
    }
});

console.log(langWithProps);

What is the best way to compare two arrays of different lengths in JavaScript?

Answer №1

Answer №2

Answer №3

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