I'm trying to accomplish this task:
require('./config/enviroment.js')(app, express);
However, I am unsure of the proper method...
I attempted:
require './config/routes.js'(app, routes) ->
Resulting in:
require('./config/routes.js'(app, routes)(function() {}));
Which I believe is not what I need.
I also tried:
require './config/enviroment.js'(app, express)
But received:
require('./config/enviroment.js'(app, express));
When it comes to invoking a function that is the output of another function, there are various methods:
f(args1) args2
f(args1)(args2)
(f args1) args2
(f args1)(args2)
Therefore, in your particular scenario:
require('./config/enviroment.js') app, express
require('./config/enviroment.js')(app, express)
(require './config/enviroment.js') app, express
(require './config/enviroment.js')(app, express)
Yes, you have the ability to execute that action.
Utilizing Coffeescript:
envVariables = require('./config/enviroment.js')(app, express)
This will be translated as:
var envVariables;
envVariables = require('./config/enviroment.js')(app, express);
Always keep in mind that this is simply JavaScript at its core.
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