What is the best way to arrange an array of objects based on a specific condition

Question

What is the best way to arrange an array of objects based on a specific condition

I have an array of objects that contain properties.

My goal is to sort them by status in a specific order: 15, 17, and then 16 using JavaScript.

In this array of objects, any object with a status value of 16

should be placed at the end, while the rest should be sorted in ascending order based on the status property.

How can I achieve this in JavaScript?

var result = arrobj.filter(e => e.details.status !== 16).sort((a, b) => a.status - b.status);

var arrobj = [
  {
    "id":1,
    "name":'xyz',
    "details": {
    "job": 'fulltime',
    "status": 15
    }
  },
  { 
    "id":2,
    "name": 'abc',
    "details": {
    "job": 'partime',
    "status": 16
    }
  },
  { 
    "id":3,
    "name": 'zen',
    "details": {
    "job": 'fulltime',
    "status": 17
    }
  },
  { 
   "id":5,
    "name": 'abu',
    "details": {
    "job": 'fulltime',
    "status": 16
    }
  },
{ 
   "id":7,
    "name": 'john',
    "details": {
    "job": 'parttime',
    "status": 15
    }
  },
 { 
   "id":10,
    "name": 'jocob',
    "details": {
    "job": 'fulltime',
    "status": 17
    }
  }
]

Expected Output

[
  {
    "id":1,
    "name":'xyz',
    "details": {
    "job":: 'fulltime',
    "status": 15
    }
  },
 { 
   "id":7,
    "name":'john',
    "details": {
    "job":: 'parttime',
    "status": 15
    }
  },
  { 
    "id":3,
    "name":'zen',
    "details":: {
    "job":: 'fulltime',
    "status": 17
    }
  },
 { 
   "id":10,
    "name"': 'jocob',
    "details":: {
    "job":: 'fulltime',
    "status": 17
    }
  },
  { 
    "id":: 2,
    "name"::~ 'abc",
    "details"::~ {
    "job"~~: 'partime',
    "status": 16
    }
  },
  { 
   ~'id": 5,
    ~'name":~ 'abu',
    ~'details"": {
    ~~'job"": 'fulltime',
    ~~'status''':' 16
    ~}
  }
]

javascript arrays loops sorting object

Answer 1

Answer №1

To create custom sorting rules, we can utilize the compareFn parameter within the Array.prototype.sort(compareFn) method.

For example:

var sortedResults = arrayObjects
    .sort((firstObj, secondObj) => {
        let x = firstObj.data.type
        let y = secondObj.data.type
        if (x === 14) x = Number.MAX_SAFE_INTEGER
        if (y === 14) y = Number.MAX_SAFE_INTEGER
        return x - y
    })

Answer 2

To create custom sorting rules, we can utilize the compareFn parameter within the Array.prototype.sort(compareFn) method.

For example:

var sortedResults = arrayObjects
    .sort((firstObj, secondObj) => {
        let x = firstObj.data.type
        let y = secondObj.data.type
        if (x === 14) x = Number.MAX_SAFE_INTEGER
        if (y === 14) y = Number.MAX_SAFE_INTEGER
        return x - y
    })

Answer 3

Answer №2

const orderedResults = [...objectArray.filter(obj => obj.details.status !== 16).sort((a,b) => a.details.status - b.details.status), ...objectArray.filter(obj => obj.details.status === 16)]

Are you referring to this code snippet?

Answer 4

const orderedResults = [...objectArray.filter(obj => obj.details.status !== 16).sort((a,b) => a.details.status - b.details.status), ...objectArray.filter(obj => obj.details.status === 16)]

Are you referring to this code snippet?

Answer 5

Answer №3

ES5 Solution

 arrObjects.sort((first, second) => {
     if (first.info.state === 16) {
         return 1;
     } else if (second.info.state === 16) {
         return -1
     } else {
         return first.info.state - second.info.state
     }
  })

Answer 6

ES5 Solution

 arrObjects.sort((first, second) => {
     if (first.info.state === 16) {
         return 1;
     } else if (second.info.state === 16) {
         return -1
     } else {
         return first.info.state - second.info.state
     }
  })

Answer 7

Answer №4

In the latest version of EcmaScript, Array.sort has been updated to be stable. This means that you can divide complex sorting tasks into two steps - first by status, and then by moving all items with a status of 16 to the end. However, this may not be the most efficient solution.

arrobj.sort((first, second) => first.details.status - second.details.status)
      .sort((first, second) => (first.details.status === 16) - (second.details.status === 16));

Answer 8

In the latest version of EcmaScript, Array.sort has been updated to be stable. This means that you can divide complex sorting tasks into two steps - first by status, and then by moving all items with a status of 16 to the end. However, this may not be the most efficient solution.

arrobj.sort((first, second) => first.details.status - second.details.status)
      .sort((first, second) => (first.details.status === 16) - (second.details.status === 16));

Answer 9

Answer №5

This code snippet can also be used for your specific situation. You were almost there!

arrobj.filter(element => element.details.status !== 16).sort((x, y) => {return x.details.status - y.details.status}).concat(arrobj.filter(element => element.details.status == 16));

Answer 10

This code snippet can also be used for your specific situation. You were almost there!

arrobj.filter(element => element.details.status !== 16).sort((x, y) => {return x.details.status - y.details.status}).concat(arrobj.filter(element => element.details.status == 16));

Answer 11

Answer №6

Your previous implementation of the sort function needs revision. Here is an improved version that also allows for changing the sort order.

// Function to sort by status
function sortByStatus(array, asc = true) {
  let newArray = [...array];

  // Filter and sort based on status
  if (asc) {
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status > b.details.status && 1 || -1);
  } else {
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status < b.details.status && 1 || -1);
  }

  return newArray;
}

// Merge the sorted result
const arrobj = [{
    "id": 1,
    "name": 'xyz',
    "details": {
      "job": 'fulltime',
      "status": 15
    }
},
{
    "id": 2,
    "name": 'abc',
    "details": {
      "job": 'partime',
      "status": 16
}
...
];

const result = [...sortByStatus(arrobj), arrobj.filter(e => e.details.status === 16)];

var arrobj = [{...}];  // Array object containing data omitted for brevity

function sortByStatus(array, asc = true) {
  let newArray = [...array];

  if (asc) {  // Sorting in ascending order
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status > b.details.status && 1 || -1);
  } else {  // Sorting in descending order
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status < b.details.status && 1 || -1);
  }

  return newArray;
}

const result = [...sortByStatus(arrobj), arrobj.filter(e => e.details.status === 16)];
console.log(result);

Answer 12

Your previous implementation of the sort function needs revision. Here is an improved version that also allows for changing the sort order.

// Function to sort by status
function sortByStatus(array, asc = true) {
  let newArray = [...array];

  // Filter and sort based on status
  if (asc) {
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status > b.details.status && 1 || -1);
  } else {
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status < b.details.status && 1 || -1);
  }

  return newArray;
}

// Merge the sorted result
const arrobj = [{
    "id": 1,
    "name": 'xyz',
    "details": {
      "job": 'fulltime',
      "status": 15
    }
},
{
    "id": 2,
    "name": 'abc',
    "details": {
      "job": 'partime',
      "status": 16
}
...
];

const result = [...sortByStatus(arrobj), arrobj.filter(e => e.details.status === 16)];

var arrobj = [{...}];  // Array object containing data omitted for brevity

function sortByStatus(array, asc = true) {
  let newArray = [...array];

  if (asc) {  // Sorting in ascending order
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status > b.details.status && 1 || -1);
  } else {  // Sorting in descending order
    newArray = newArray.filter(e => e.details.status !== 16).sort((a, b) => a.details.status < b.details.status && 1 || -1);
  }

  return newArray;
}

const result = [...sortByStatus(arrobj), arrobj.filter(e => e.details.status === 16)];
console.log(result);

Answer 13

Answer №7

One way to ensure that objects with status 16 are placed at the end of your array is by including .status in the sorting function sort(). To achieve this, I created a separate array specifically for objects with the status of 16 and then appended it to the end of the original array containing all other objects.

var sortedArray = originalArray.filter(item => item.details.status !== 16)
                                .sort( (a, b) => a.details.status - b.details.status);
sortedArray = sortedArray.concat(originalArray.filter(item => item.details.status === 16));

console.log(sortedArray)

Answer 14

One way to ensure that objects with status 16 are placed at the end of your array is by including .status in the sorting function sort(). To achieve this, I created a separate array specifically for objects with the status of 16 and then appended it to the end of the original array containing all other objects.

var sortedArray = originalArray.filter(item => item.details.status !== 16)
                                .sort( (a, b) => a.details.status - b.details.status);
sortedArray = sortedArray.concat(originalArray.filter(item => item.details.status === 16));

console.log(sortedArray)

What is the best way to arrange an array of objects based on a specific condition

Answer №1

Answer №2

Answer №3

Answer №4

Answer №5

Answer №6

Answer №7

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