let values = dataSku.map(sku => {return map.skuInfo[sku].description})
If map.skuInfo[sku] can potentially be null or undefined, how can I filter it out?
let values = dataSku.map(sku => {return map.skuInfo[sku].description})
If map.skuInfo[sku] can potentially be null or undefined, how can I filter it out?
It seems like you are looking for a solution using the .filter
method. This function is similar to .map
and can help you filter out specific items based on certain conditions.
const values = dataSku
.filter(item => item.description !== undefined)
Depending on your data structure, the Array.filter documentation on MDN can provide more insights on how to use it effectively. This method removes all non-truthy return values from the array.
Your issue can be resolved with the following solution -
const itemDescriptions = dataSku.map(sku => map.skuInfo[sku]}).filter(skuInfo => typeof skuInfo !== "undefined").map(skuInfo => skuInfo.description);
Here is a possible solution:
const properties = dataList.map(item => {
if (!propertyList.item) return;
return propertyList.item.description
})
This block of code will exit the function if propertyList.item
evaluates to false.
You can use the following code snippet:
const filterNotNullAndUndefined = (sku) => (sku?.description !== null && sku?.description !== undefined);
const filterNotNUllAndUndefinedAndNonEmpty = (sku) => (sku?.description)
const sku = [
{id: 1, 'description': '1'},
{id: 2, 'description': null},
{id: 3, 'description': undefined},
{id: 4, 'description': ''},
null,
undefined
];
const result1 = sku?.filter(filterNotNUllAndUndefinedAndNonEmpty);
const result2 = sku?.filter(filterNotNullAndUndefined);
console.log(result1);
console.log(result2);
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